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chubhunter [2.5K]
3 years ago
10

Gary has 63 counters.he pura them in an array with 9 columbs how many rows are there

Mathematics
1 answer:
Mice21 [21]3 years ago
4 0
There are 7 rows.
63/9 = 7.
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It is estimated that the average amount owed for student loans in 2010 was $25,250 per student.  If the interest rate for studen
Nostrana [21]
Given:
loan amount: 25,250
original interest rate: 3.4%
new interest rate: 6.8%
term: 10 years.

Assuming that simple interest formula is used.
I = P * r * t
I = interest
P = principal
r = interest rate
t = term/time

I = 25,250 * 3.4% * 10 years
I = 8,585

I = 25,250 * 6.8% * 10 years
I = 17,170

17,170 - 8,585 = 8,585 Additional interest paid using the new interest rate.

Using an online loan repayment calculator: Here are the following data:
Loan Balance:$25,250.00
Adjusted Loan Balance:$25,250.00Loan
Interest Rate:6.80%
Loan Fees:0.00%
Loan Term:10 years
Minimum Payment:$0.00
Monthly Loan Payment:$290.58
Number of Payments:120
Cumulative Payments:$34,869.23
Total Interest Paid:$9,619.23

<span><span>Loan Balance:$25,250.00
</span><span>Adjusted Loan Balance:$25,250.00
</span><span>Loan Interest Rate:3.40%
</span><span>Loan Fees:0.00%
</span><span>Loan Term:10 years
</span><span>Minimum Payment:$0.00</span>
<span>Monthly Loan Payment:$248.51
</span><span>Number of Payments:120</span>
<span>Cumulative Payments:$29,820.59
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6 0
3 years ago
A jar contains 10 marbles marked with the numbers 1 through 10. You pick a marble at random. What is the probability of not pick
mr_godi [17]

Answer:

9/10

Step-by-step explanation:

Since there is only one marble per number and there is only one marble for the number 8 you would take just subtract 10-1 which would give you 9.

5 0
2 years ago
The home run percentage is the number of home runs per 100 times at bat. A random sample of 43 professional baseball players gav
Andru [333]

Step-by-step explanation:

(a) Yes, if you enter all 43 values into your calculator, you calculator should report:

xbar = 2.293

s = 1.401

(b)

Note: Most professors say that is sigma = the population standard deviation is unknown (as it is unknown here), you should construct a t-confidence interval.

xbar +/- t * s / sqrt(n)

2.293 - 1.684 * 1.401 / sqrt(43) = 1.933

2.293 - 1.684 * 1.401 / sqrt(43) = 2.653

Answer: (1.933, 2.653)

Note: To find the t-value that allows us to be 90% confident, go across from df = 43-1 = 42 (round down to 40 to be conservative since 42 in not in the table) and down from (1-.90)/2 = .05 or up from 90% depending on your t-table. So, the t-critical value is 1.684.

Note: If you can use the TI-83/84, it will construct the following CI using df = 42 (ie t = 1.681).

2.293 +/- 1.681 * 1.401 / sqrt(43)

(1.934, 2.652)

Note: Some professors want you to construct a z-CI when the sample size is large. If your professor says this, the correct 90% CI is:

2.293 +/- 1.645 * 1.401 / sqrt(43)

(1.942, 2.644)

Note: To find the z-value that allows us to be 90% confident, (1) using the z-table, look up (1-.90)/2 = .05 inside the z-table, or (2) using the t-table, go across from infinity df (= z-values) and down from .05 or up from 90% depending on your t-table. Either way, the z-critical value is 1.645.

(c)

Note: Again, most professors say that is sigma = the population standard deviation is unknown (as it is unknown here), you should construct a t-confidence interval.

xbar +/- t * s / sqrt(n)

2.293 - 2.704 * 1.401 / sqrt(43) = 1.715

2.293 - 2.704 * 1.401 / sqrt(43) = 2.871

Answer: (1.715, 2.871)

Note: To find the t-value that allows us to be 99% confident, go across from df = 43-1 = 42 (round down to 40 to be conservative since 42 in not in the table) and down from (1-.99)/2 = .005 or up from 99% depending on your t-table. So, the t-critical value is 2.704.

Note: If you can use the TI-83/84, it will construct the following CI using df = 42 (ie t = 2.698).

2.293 +/- 2.698 * 1.401 / sqrt(43)

(1.717, 2.869)

Note: Again, some professors want you to construct a z-CI when the sample size is large. If your professor says this, the correct 99% CI is:

2.293 +/- 2.576 * 1.401 / sqrt(43)

(1.742, 2.843)

Note: To find the z-value that allows us to be 99% confident, (1) using the z-table, look up (1-.99)/2 = .005 inside the z-table, or (2) using the t-table, go across from infinity df (= z-values) and down from .005 or up from 99% depending on your t-table. Either way, the z-critical value is 2.576.

(d)

Tim Huelett 2.5

Since 2.5 falls between (1.715, 2.871), we see that Tim Huelett falls in the 99% CI range. So, his home run percentage is NOT significantly different than the population average.

Herb Hunter 2.0

Since 2.0 falls between (1.715, 2.871), we see that Herb Hunter falls in the 99% CI range. So, his home run percentage is NOT significantly different than the population average.

Jackie Jensen 3.8.

Since 3.8 falls above (1.715, 2.871), we see that Jackie Jensen falls in the 99% CI range. So, his home run percentage IS significantly GREATER than the population average.

(e)

Because of the Central Limit Theorem (CLT), since our sample size is large, we do NOT have to make the normality assumption since the CLT tells us that the sampling distribution of xbar will be approximatley normal even if the underlying population distribution is not.

6 0
3 years ago
All 6 members of the Valastro family have decided to
atroni [7]

Answer:

5

Step-by-step explanation:

7 0
2 years ago
Find the equation of the circle that satisfies the given conditions. radius 4 and center (3, -1)?
dmitriy555 [2]
<span> the equation of this circle is (x - 3)² + (y + 1)² = 4²</span>
5 0
3 years ago
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