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olga55 [171]
3 years ago
13

Which is greater -0.04 or 0.05

Mathematics
2 answers:
irakobra [83]3 years ago
5 0
0.05 because 5 is bigger than 4 plus 4 is negative
Firlakuza [10]3 years ago
5 0
0.05 is the answer for your question
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Can someone please solve both of these showing all the steps I'll add extra points because its two​
EastWind [94]

Answer:

4. 21

5. 32

Step-by-step explanation:

First question:

sin(x) = opp/hyp = 22/63 = 0.3492

x = sin⁻¹(0.3492)

20.43. Rounded to the nearest degree, it would be 21.

Second question:

sin(x) = opp/hyp = 18/34 = 0.5294

x = sin⁻¹(0.5294)

31.96. Rounded to the nearest degree, it would be 32.

Let me know if you have any problems.

3 0
3 years ago
I need help on 11,13,14,15
vlabodo [156]
Use photomath... but i already did 11 and its -52
6 0
3 years ago
What is the coefficient and the constant in 4+x=15?
Dmitriy789 [7]
Problem: 4+x=15
- Subtract 4 from both sides
4+x-4=15-4
- Refine
x = 11
7 0
3 years ago
The conditional relative frequency table below was generated by column using frequency table data comparing the number of calori
inessss [21]

Answer:

B. There is an association because the value 0.15 is not similar to the value 0.55

Step-by-step explanation:

Based on the above picture, for the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.

The conditions that satisfy whether there exists an association between conditional relative frequencies are:

1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.

2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.

For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45

We can conclude that there is an association because the value 0.15 is not similar to the value 0.55

3 0
3 years ago
Read 2 more answers
Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0
skad [1K]
\bf x^2+y^2-6y-8=0\qquad &#10;\begin{cases}&#10;x^2+y^2=r^2\\\\&#10;y=rsin(\theta)&#10;\end{cases}\implies r^2-6rsin(\theta)=8&#10;\\\\\\&#10;\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8&#10;\\\\\\\&#10;[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby &#10;\begin{array}{llll}&#10;\textit{so we need a value there to make}\\&#10;\textit{a perfect square trinomial}&#10;\end{array}

\bf 6rsin(\theta)\iff 2\cdot r\cdot  \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}&#10;\\\\\\&#10;\textit{now, bear in mind we're just borrowing from zero, 0}&#10;\\\\&#10;\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}

\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\&#10;\left. \qquad  \right.\uparrow \\&#10;\textit{so-called "completing the square"}&#10;\\\\\\\&#10;[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)&#10;\\\\\\&#10;r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)
3 0
3 years ago
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