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Alexeev081 [22]
2 years ago
11

Cody claims that when 1/6 is multiplied by a negative number, the results will always be less than 1/6. Do you agree with Cody?

Explain. Give examples to support your answer.
Mathematics
1 answer:
Fittoniya [83]2 years ago
3 0

Answer:yes, I agree with Cody

Step-by-step explanation:

According to Cody's claim, when 1/6 is multiplied by a negative number, the results will always be less than 1/6. This is true because the result would be a negative number. A negative number is always lesser than a positive number. For example, if 1/6 is multiplied by -1, the result would be - 1/6. If 1/6 is multiplied by -10, the result would be - 1/60. 1/6 is multiplied by -20, the result would be - 1/-120. The results of - 1/6, - 1/60 and - 1/120 would always be on the left of the zero point on a number line while 1/6 will always be on the right side of zero on the number line. Numbers on the right side of zero are always greater than numbers on the left side of zero on the number line.

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If c = 42 -d is true, then which is greater: cord, or are you not able to tell? Explain how you
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Step-by-step explanation:

4 0
2 years ago
The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.
Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

h(t)=-16t^2+80t+64

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A)  Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

-16t^2+80t+64=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+80t+64=0

so

a=-16\\b=80\\c=64

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}

t=\frac{-80\pm\sqrt{10,496}} {-32}

t=\frac{-80+\sqrt{10,496}} {-32}=-0.70

t=\frac{-80-\sqrt{10,496}} {-32}=5.70

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

-16t^2+80t+64=40

-16t^2+80t+24=0

Solve the quadratic equation

we have

a=-16\\b=80\\c=24

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}

t=\frac{-80\pm\sqrt{7,936}} {-32}

t=\frac{-80+\sqrt{7,936}} {-32}=-0.28

t=\frac{-80-\sqrt{7,936}} {-32}=5.28

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0
3 years ago
A circular pool has a radius of 10 feet. what is the area of the surface if the water? use 3.1r as pi
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No use 3.14
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Whoever has the best answer gets the brainliest answer!:)
Korvikt [17]
Since the length is 10 in. You must multiply it by \frac{1}{5} and then multiply by \frac{1}{2}. The reason for this is because if you divide ten by 5 it will be 2, then if you divide 2 by 2 it will be 1.
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