Answer:
10.1 years.
Step-by-step explanation:
It is given that,
Principal = 9000
Rate of interest = 5%
No. of times interest compounded = 2 times in an year
Amount after certain time = 14800
The formula for amount:
where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.
Substitute the given values in the above formula.
Taking log both sides.
![[\because \log a^b=b\log a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20a%5Eb%3Db%5Clog%20a%5D)
Therefore, the required time is 10.1 years.
Answer:
- 43t - 22s - 3
Step-by-step explanation:
(–45t + 53s) + (–3 – 75s + 2t)
Opening the brackets
-45t + 53s -3 - 75s + 2t
Collecting like terms
-45t + 2t + 53s - 75s -3
Simplify the expression
-43t -22s - 3
Answer:
15.5? Im assuming as a pa rt of my calculations!
Step-by-step explanation:
Answer:
function
Step-by-step explanation:
every x value has only 1 y value
Answer:
g( f(2)+3) = 30
Step-by-step explanation:
<u>step(i)</u>:-
Given function g(t)=t²-t and f(x)=1+x
given f(x)=1+x
f(2) = 1 + 2 =3
<u><em>step(ii)</em></u>:-
g( f(2)+3) = g(3 + 3)
= g(6)
= (6)² - 6
= 36 -6
= 30
<u><em>Conclusion</em></u>:-
g( f(2)+3) = 30
