The equation for a parabola can also be written in the "vertex form":
y = a (x - h) ^ 2 + k
In this equation, the vertex of the parabola is the point (h, k).
We have then:
y = 2x2 + 16x + 17
We look for the vertice:
0 = 4x + 16
x = -16 / 4
x = -4
Substituting:
y = 2 * (- 4) ^ 2 + 16 * (- 4) +17
y = -15
Substituting the given point:
y = 2 (x +4) ^ 2 - 15
Answer:
y = 2 (x +4) ^ 2 - 15
option C
Make bottom number same
ok, so remember
(a-b)(a+b)=a²+b²
so
to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)
so multiply 2nd fraction by (y+x)/(y+x)

=

=
Im so sorry I don't know how to do B but I do know a and c.....
A) 1.44
C) 3
The values are vx =
, vw =
and m∠x = 45°, for the given right angle diagram.
Step-by-step explanation:
The given is,
Right angled triangle XVW,
XW = 14
m∠V = 90°
m∠W = 45°
Step:1
Given diagram is right angle triangle,
Trigonometric ratios for right angle is,
∅
............................(1)
∅
.........................(2)
∅
..........................(3)
Step:2
For the value of VX,
∅ 
From given,
∅ = 45°
XW = 14
Above equation becomes,
45 
Where, Sin 45 =
,

Step:3
For the value of VW,
∅ 
From given,
∅ = 45°
XW = 14
Above equation becomes,
45 
Where, cos 45 =
,

Step:4
For the value m∠x = a,
a 
From given,
VX = 
VW = 
Above equation becomes,
a 
a = 1
a =
(1)
a = 45°
m∠x = a = 45°
Step:5
Check for solution,
m∠v = m∠w + m∠x
= 45° + 45°
90° = 90°
Result:
The values are vx =
, vw =
and m∠x = 45°, for the given right angle diagram.
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