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3 years ago

Is 6200 ft greater or less than 1 mile 900 ft

2 answers:

7 0

1 mile is equal to 5280 feet

Add 900 to it:

5280 + 900 = 6180

6180 is less than 6200, so 1 mile and 900 feet is less than 6200 feet.

Semenov [28]3 years ago

3 0

It is less than 6200 ft

Your welcome :)

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What is the simplified form of left parenthesis 27 x to the power of negative six end power y to the power of 12 end power right

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5 0

3 years ago

-40+8p-3z identify the coefficents and like terms

Oxana [17]

Answer:

there are no like terms in this so thats your answer

Step-by-step explanation:

7 0

2 years ago

2. The 7th term of an A.P is 27 and the 12th term is 47, what is the sequence?

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

let r be the common differenc of the sequence

Term 12 - Term 7 = (12 - 7)r

then

47 - 27 = 5r

then

20 = 5r

then

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then

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then

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<em><u>therefore </u></em>

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8 0

3 years ago

PLEASE HELP MEEEE HURRRY!!! :)

sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

$\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}$

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

$\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}$ First, I swapped the first and third rows.

$\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}$ Leading coefficient of row 2 canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}$ The start value of row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}$ Matrix rows 2 and 3 were swapped.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}$ Leading coefficient in row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}$

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

$\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}$

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!

fgiga [73]

Answer:

The number of questions he finished will be q.

37 + q = 78

rewrite this

78 - 36 = q

solve

78 - 36 = 42

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3 years ago