What is the lateral surface area of a cylindrical-shaped candle with a radius of 3 cm and a height of 15 cm? (Use 3.14 for .) A.
847.8 sq cm B. 45 sq cm C. 282.6 sq cm D. 339.12 sq cm
1 answer:
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Answer:
x=36
Step-by-step explanation:
So, lets go over what we know:
16 is equal to 4/9ths of x.
As a equation, this looks like:
We can begin to solve for x by multiplying both sides by the denominator, 9, which gets us:
=
Then we can divide by the coefficent of x, which is 4, to get our answer:
=
This is our answer! Hope this helps! :3
Answer:
y = sin(x- pi/2)
Step-by-step explanation:
Please see the attached image to see your graphs.
By simple inspection we can see that the sine is shifted pi/2 to the right.
We know this because sines are periodic functions with a period T = 2*pi
We can also see that the maximum point of the graph (y = 1) got shifted by a fourth of the period.
And finally, since we want to shift the graph to the right, we need to substract from the argument of the sine term.
