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2 years ago

Austin is 69 years younger than Jamie. 3 years ago, Jamie's age was 4 times Austin's age. How old is Austin now?

Mathematics

1 answer:

matrenka [14]2 years ago

4 0

Answer: 26 years old

Step-by-step explanation:

Create an equation with Austin as x and Jamie as x+69 (I just like workin with addition signs more)= 4(x-3)= x+69-3
Simplify the equations --> 4x-12=x+66
Solve the equation: 3x-12=66 --> 3x=78 --> x=26

This is the same as other age problems, just with the extra step of distributing the multiplication.

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10.222 in a fraction

liq [111]

5111/500 or 10 111/500

8 0

3 years ago

Evaluate 5 - 44 * (-0.75) - 18 / 2/3 * 0.8 + (-4/5)

jenyasd209 [6]

Answer:

15.6

step by step explanation:

5-44• (-0.75) - 18 ÷ 2/3 • 0.8 + (-4/5)

= 5 + 33 - 27*0.8 - 0.8

= 5 + 33 -21.6 - 0.8

= 15.6.

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2 years ago

4 3/4 X 4 1/7 what is it please help

Y_Kistochka [10]

first you turn the fractions into inproper fractions by multiplying the whole number by the denomonator and adding the numerator

4×4=16

16+3=19

19/4

4×7=28

28+1=29

29/7

keep the denomonators the same. now that you've converted them into inproper fractions you can multiply them

19/4 × 29/7=551/28

there is no way to simplify this answer so this is the final answer

7 0

3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago

A certain tennis player makes a successful first serve 6969% of the time. Suppose the tennis player serves 9090 times in a matc

Wewaii [24]

Answer:

a) 4.387

b) Yes, because np & npq are greater than 10.

c) = 0.017

Step-by-step explanation:

Give data:

p = 0.69

n = 90

a) a

E(X) = np = 62.1

$SD(X) = \sqrt{(np(1-p))}$

$=\sqrt{90\times 0.69(1- 0.69)}$

= 4.387

np = 62.1

q = 1 - p = 1 - 0.69 = 0.31

npq = 19.251

Yes, because np & npq are greater than 10.

$P(X \geq 72 ) = P(X > 71.5)$ [continuity correction]

$= P(Z> \frac{((71.5-62.1)}{ 4.387})$

= P(Z> 2.14 )

= 1 - P(Z<2.14)

= 1 - 0.983 (using table)

= 0.017

8 0

3 years ago