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777dan777 [17]
4 years ago
15

Which word describes the slope of the line? positive negative zero undefined

Mathematics
2 answers:
Margaret [11]4 years ago
8 0

Answer:

Zer0

Step-by-step explanation:

If a linear line is parallel to the x-axis, in other words, it is horizontal, the slope has to be 0.

There is no steepness to the line, and steepness is essentially what slope is.

Hope this helps!!

irina1246 [14]4 years ago
4 0

Answer: Zero

Step-by-step explanation:

A zero line on a graph means there's no positive nor negative line on the graph.

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Savatey [412]

The coordinates of point B are (-4 , -2) ⇒ answer H

Step-by-step explanation:

In any circle

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If (x , y) are the coordinates of the mid-point of a line whose end

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Learn more:

You can learn more about the circle in brainly.com/question/9510228

#LearnwithBrainly

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3 years ago
For the straight line defined by the points (4,57) and (6,91) , determine the slope ( m ) and y-intercept ( ???? ). Do not round
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\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{57})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{91}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{91}-\stackrel{y1}{57}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{4}}}\implies \cfrac{34}{2}\implies 17 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{57}=\stackrel{m}{17}(x-\stackrel{x_1}{4})\implies y-57=17x-68

\bf y=17x-11\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad \begin{cases} \stackrel{slope}{17}\\\\ \stackrel{y-intercept}{(0,-11)} \end{cases}

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