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serious [3.7K]
3 years ago
12

What is 11/15 - 3/20

Mathematics
2 answers:
faust18 [17]3 years ago
6 0
11/15 - 3/20
= 11/(3*5) - 3/(4*5)
= (11*4)/(3*4*5) - (3*3)/(3*4*5)
= (44 - 9)/(3*4*5)
= 35/(3*4*5)
= (7*5)/(3*4*5)
=7/12
otez555 [7]3 years ago
3 0
The answer is 0.5833
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Answer:

X-8

Step-by-step explanation:

Thats it.

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3 years ago
(1/12)^-2b•12^-2b+2=12?
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Step-by-step explanation:

(1/12)^-2b x 12^-2b+2=12

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2 years ago
The mayor sample of 1300 data, a political more than 31%. Testing voters in the town and found that 34% of the residents favored
fiasKO [112]

Answer:

z=\frac{0.34 -0.31}{\sqrt{\frac{0.31(1-0.31)}{1300}}}=2.339  

p_v =P(Z>2.339)=0.0097  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion the residents favored annexation is hgiher than 0.31 or 31%.  

Step-by-step explanation:

1) Data given and notation

n=1300 represent the random sample taken

\hat p=0.34 estimated proportion of residents favored annexation

p_o=0.31 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.31:  

Null hypothesis:p\leq 0.31  

Alternative hypothesis:p > 0.31  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.34 -0.31}{\sqrt{\frac{0.31(1-0.31)}{1300}}}=2.339  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.339)=0.0097  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion the residents favored annexation is hgiher than 0.31 or 31%.  

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Answer:

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Answer:

solution y=271 or rewrite y-271=0

Step-by-step explanation:

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