corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color c)the marbles are different in color
Answer:
Step-by-step explanation:
<u><em>The probability was done with replacement.</em></u>
Probaility of an event happening
number of blue marbles= 2
number of green marbles=5
total number of marbles=7
(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)


(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)



(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)



Well 50% of 30,000 is 15,000
So 10% is 3,000
15,000 - 3,000 = 12,000
So 40% increase is 42,000
22/100:
You can actually divided the numerator and denominator by a number that can go into both 22 and 100 but also not get a remainder.
So 22/2= 11
And 100/2=50
Combined you get 11/50
Hope it helps!!!
Answer:
153.94
Step-by-step explanation:
If you want it not rounded its
153.9380400259 inches
3 times flipped, two sides fo a coin heads and tails, 2/3 meaning most likely