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Hatshy [7]
3 years ago
6

On Monday Godswill ate some grapes. On Tuesday he

Mathematics
2 answers:
Sav [38]3 years ago
7 0

For this case we have to:

Let "x" be the variable that represents the number of grapes Godswill ate on Monday, so we have:

  • Monday:x
  • Tuesday:x + 6
  • Wednesday:(x + 6) + 6 = x + 12
  • Thursday: [(x + 6) +6] + 6 = x + 18
  • Friday:{[(x + 6) +6] +6} + 6 = x + 24

Finally we have the following expression:

x + x + 6 + x + 12 + x + 18 + x + 24 = 100

We add similar terms:

5x + (6 + 12 + 18 + 24) = 100\\5x + 60 = 100\\5x = 100-60\\5x = 40\\x = \frac {40} {5}\\x = 8

So, on Monday he ate 8 grapes

Answer:

On Monday he ate 8 grapes.

garri49 [273]3 years ago
5 0

Answer: He ate 8 grapes on Monday.

Step-by-step explanation:

Let be "x" the number of grapes Godswill ate on Monday.

You know that he ate 6 more grapes than he had on Monday. This can be expressed with:

x+6

Since each day that week, he ate 6 more grapes than the day before and he realized on Friday he had eaten a total of 100 grapes this week, you can write the following expression and solve for "x":

x+(x+6)+(x+12)+(x+18)+(x+24)=100\\\\5x+60=100\\\\x=\frac{40}{5}\\\\x=8

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The given set has 4 elements, so it has 2⁴ = 16 subsets and 2⁴ - 1 = 15 proper subsets.

Just to illustrate the claim, we have

• subsets of size 0 (1 of these):

{ } (empty set)

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{1/6, 1/7}, {1/6, 1/8}, {1/6, 1/9}, {1/7, 1/8}, {1/7, 1/9}, {1/8, 1/9}

• subsets of size 3 (4 of these):

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• subsets of size 4 (1 of these):

{1/6, 1/7, 1/8, 1/9}

and the last one is the only subset that is not a proper subset, because that subset = the set.

6 0
2 years ago
The local grocery store has sorted apples by size. The distribution is approximately normal. The large apples have a mean diamet
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Answer:

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PSYCHO15rus [73]
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A

Step-by-step explanation:

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