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olga55 [171]
3 years ago
11

What would be likely to happen to the rate of cellular respiration if you placed germinating seeds in an airtight container? Cel

lular respiration would be likely to decrease due to decreasing CO2 Cellular respiration would be likely to increase due to increasing O2 Cellular respiration would be likely to slow due to decreasing O2 Cellular respiration would be likely to increase due increased need for cellular energy
Biology
1 answer:
Ahat [919]3 years ago
7 0

Answer:

Cellular respiration would be likely to slow due to decreasing O2

Explanation:

One of the essential factors for germination to proceed is the presence of oxygen. The embryo within the seed needs to respire to get the much needed energy to drive the various metabolic activities that eventually leads to the emergence of the embryo from the seed coat (germination).

During respiration, the energy locked up in foods is released in a multiple-steps reaction whose summary goes thus;

                    C_6H_1_2O_6 + 6O_2 -------> 6CO_2 + 6H_2O + energy

<em>Hence, if germinating seeds are placed in an airtight container, the much needed oxygen for respiration will be limited, resulting in the slowing down of cellular respiration due to inadequate oxygen. If the condition persists much longer, cellular respiration will cease completely and the seeds will die off.</em>

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calculate the mass defect for oxygen-16 given this data: mass of an oxygen-16 atom: 15.994914 amu mass of a proton: 1.00728 amu
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The answer is <span>0.132606 amu.</span>

The mass defect (Δm) is the total mass of protons and neutrons minus the mass of the atom. 
<span>mass of an oxygen-16 atom: 15.994914 amu
mass of a proton: 1.00728 amu
mass of a neutron: 1.00866 amu
</span>
An oxygen atom has 8 protons and 8 neutrons. Therefore:
Δm = 8 · 1.00728 + 8 · 1.00866 - <span>15.994914 = 8.05824 + 8.06928 - 15.994914 = 0.132606 amu
</span>
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