I am a 3-digit number that is even. My hundreds and ones digits are the same and have a sum of 8. My tens digit is 2 less than m
2 answers:
Let's start off with some key terms.
The number has 3 digits.
Even numbers end with 0, 2, 4, 6, or 8. (Obviously)
The hundreds digit and ones digit are the same.
First number in a 3 digit number is the hundreds, and the last number is the ones.
So, both of those two digits are the same and has to equal 8.
Well,
The hundreds place and the ones place are 4.
The tens digit is the middle number in a 3-digit number.
It is two numbers less than the ones digit.
The number is 424.
The number has 3 digits.
Even numbers end with 0, 2, 4, 6, or 8. (Obviously)
The hundreds digit and ones digit are the same.
First number in a 3 digit number is the hundreds, and the last number is the ones.
So, both of those two digits are the same and has to equal 8.
Well,
The hundreds place and the ones place are 4.
The tens digit is the middle number in a 3-digit number.
It is two numbers less than the ones digit.
The number is 424.
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Let numbers of books be 'b' and numbers of CDs be 'c'
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Equation [1] ⇒
Equation [2] ⇒
We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;
and 
, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either or the subject:
Then we substitute into Equation [2]
Now we know the value of which is , substitute this value into we have 
Answer:
Numbers of books = 13
Numbers of CDs = 7
We can set up two equations:
Equation [1] ⇒
Equation [2] ⇒
We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;
First, rearrange Equation [1] to make either
Then we substitute
Now we know the value of
Answer:
Numbers of books = 13
Numbers of CDs = 7