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LekaFEV [45]
3 years ago
11

I am a 3-digit number that is even. My hundreds and ones digits are the same and have a sum of 8. My tens digit is 2 less than m

y ones digit. What number am I ?
Mathematics
2 answers:
Nikitich [7]3 years ago
6 0
424 I know because 4+4=8 and 4-2= 2 so I figured 424
Lubov Fominskaja [6]3 years ago
3 0
Let's start off with some key terms.

The number has 3 digits.
Even numbers end with 0, 2, 4, 6, or 8. (Obviously)

The hundreds digit and ones digit are the same.
First number in a 3 digit number is the hundreds, and the last number is the ones.

So, both of those two digits are the same and has to equal 8.

Well, 4+4=8

The hundreds place and the ones place are 4.

The tens digit is the middle number in a 3-digit number.

 It is two numbers less than the ones digit.
4-2=2

The number is 424. 






\bowtie
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<1 and <2

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3 years ago
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Arlecino [84]

Answer:

-2 =x

Step-by-step explanation:

-3x-2=2x+8

Add 3x to each side

-3x+3x-2=2x+3x+8

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Subtract 8 from each side

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3 years ago
What are the solutions to the equation |x| =15 -4x?
zheka24 [161]
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5 0
3 years ago
Select the correct answer.
lidiya [134]

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Step-by-step explanation:

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8 0
1 year ago
The sides of a triangle are 1, x, and x2. what are possible values of x?
Whitepunk [10]
The sides of the triangle are given as 1, x, and x².

The principle of triangle inequality requires that the sum of the lengths of any two sides should be equal to, or greater than the third side.

Consider 3 cases
Case (a):  x < 1,
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      We require that x² + x ≥ 1
      Solve x² + x - 1 = 
      x = 0.5[-1 +/- √(1+4)] = 0.618 or -1.618.
      Reject the negative length.
     Therefore, the lengths are 0.382, 0.618 and 1.

Case (b): x = 1
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    The sides are 1, 1 and 1.

Case (c): x>1
  In increasing order, the lengths are 1, x, and x².
  We require that x + 1 ≥ x²
  Solve x² - x - 1 = 0
  x = 0.5[1 +/- √(1+4)] = 1.6118 or -0.618
  Reject the negative answr.
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Answer:
The possible lengths of the sides are
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(b) 1, 1 and 1.
(c) 2.618, 1.618 and 1.

7 0
3 years ago
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