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2 years ago

Factor completely 4x2 − 8x + 4. A Prime B 4x(x2 − 2x + 1) C 4(x2 − 2x + 1) D 4(x2 + 4)

Mathematics

2 answers:

marta [7]2 years ago

8 0

Answer:

4(x-1)(x-1)

4(x^2-2x+1) C

Step-by-step explanation:

4x^2 − 8x + 4 common factor 4

4(x^2-2x+1)

4(x-1)(x-1) or (4x-4)(x-1)

GarryVolchara [31]2 years ago

4 0

Answer:

4 ( x-1)^2

Step-by-step explanation:

4x^2 − 8x + 4.

Factor out the greatest common factor

4( x^2 -2x+1)

Factor inside the terms

4( x-1) (x-1)

4 ( x-1)^2

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Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. T

garik1379 [7]

Answer:

a) Null hypothesis: $\mu \geq 3$

Alternative hypothesis: $\mu < 3$

This hypothesis test is a left tailed test.

b) $t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784$

The p value for this case can be calculated with this probability:

$p_v =P(z$

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value $\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310$ and for the alternative we select $< \mu_o$ . Then press Calculate.

And we got the same results.

Step-by-step explanation:

Information given

$\bar X=2.8$ represent the sample mean

$s=2.6$ represent the population standard deviation

$n=1310$ sample size

$\mu_o =3$ represent the value to test

$\alpha=0.5$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:

Null hypothesis: $\mu \geq 3$

Alternative hypothesis: $\mu < 3$

This hypothesis test is a left tailed test.

Part b

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784$

The p value for this case can be calculated with this probability:

$p_v =P(z$

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value $\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310$ and for the alternative we select $< \mu_o$ . Then press Calculate.

And we got the same results.

3 0

2 years ago

Let h(x)equalsf(g(x)), where f and g are differentiable on their domains. If g(9)equalsnegative 6 and g prime(9)equals3,

artcher [175]

Answer:

Fghb

Step-by-step explanation:

was my time to

3 0

2 years ago

Please help me . I am trying to do cancellation but i am having trouble

qwelly [4]

In this question, you are only able to cancel out the (x + 5). The others are unable to be cancelled.

4 0

2 years ago

Aria paid $75,000 for her house. its property value increased by 2.2% per year. when aria sold her house after eleven years, how

Wewaii [24]

Answer:

Step-by-step explanation:

Converting percent to decimal : 2.2/100 = 0.022

Finding 2.2$ of $75k : 75,000 x 0.022 = $1,650 (also the increase in one year)

Finding how much it was worth after 11 years :

(75,000 x 0.022) x 11 = $18,150 or 1,650 x 11 = $18,150

Now add the product to the regular amount to find out the answer:

75,000 + 18,150 = $93,150 (which is how much it increased after 11 years)

3 0

1 year ago

PLEASE HELP, 30 points AND brainliest if I get an explanation :)

Nostrana [21]

Answer:

Please check the explanation.

Step-by-step explanation:

BLUE PENTAGON

The blue shape represents the Pentagon

The length of the side a = 7

As there are 5 sides.

Thus,

The Perimeter of the Blue Pentagon = P = 5a = 5(7) = 35

Using the formula to determine the area of the Pentagon

$A=\frac{1}{4}\sqrt{5\left(5+2\sqrt{5}\right)}a^2\:\:\:\:\:\:\:\:\:\:\:\:\:$

$A=\frac{1}{4}\sqrt{5\left(5+2\sqrt{5}\right)}\left(7\right)^2\:\:\:\:\:\:$

$A\approx 84.3\:\:\:$

Thus,

The Area of the Blue Pentagon = $A\approx 84.3\:\:\:$

RED PENTAGON

The red shape represents the Pentagon

The length of the side a = 4

As there are 5 sides.

Thus,

The Perimeter of the Red Pentagon = P = 5a = 5(4) = 20

Using the formula to determine the area of the Pentagon

$A=\frac{1}{4}\sqrt{5\left(5+2\sqrt{5}\right)}a^2\:\:\:\:\:\:\:\:\:\:\:\:\:$

$A=\frac{1}{4}\sqrt{5\left(5+2\sqrt{5}\right)}\left(4\right)^2\:\:\:\:\:\:$

$\:A\approx 27.5$

The Area of the Red Pentagon = $\:A\approx 27.5$

Conclusion:

The Perimeter of the Blue Pentagon = 35

The Perimeter of the Red Pentagon = 20

Thus, the ratio of the perimeter is: 35/20 = 7/4

The Area of the Blue Pentagon = 84.3 = 843/10

The Area of the Red Pentagon = 27.5 = 275/10

Thus, the ratio of the Area is:

$\frac{\frac{843}{10}}{\frac{275}{10}}=\frac{843}{275}$

7 0

2 years ago