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3 years ago

CAN SOMEONE ANSWER ASAP PLEASE!!!!! WILL GIVE EXTRA POINTS

Mathematics

1 answer:

sdas [7]3 years ago

3 0

I'm really sorry if I'm wrong but

14*26=364 so he can go 364 miles for every full tank so his first 364 are covered since he starts with a full tank.

Step 2:
838/26*14 = <span>451
</span>
step 3:

He'd only have to stop once

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22.386

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3 years ago

Nadita earned $224 last month. she earned $28 by sellinging cards at a craft fair and the rest of the money by babysitting compl

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2 years ago

Giving brainliest and thanks please help !!!!

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Answer:

2 and 4

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3 years ago

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The length of the leg of right isosceles triangle is a. Find the length of the hypotenuse.

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4 years ago

Observations of the center of the Milky Way show the presence of a super massive black hole with a mass of 4.6 x 106 solar masse

natali 33 [55]

The Schwarzschild radius of the black hole depends on its mass

The Schwarzschild radius of this supermassive black holeis 0.091 AU

<h3 /><h3>How to determine the Schwarzschild radius?</h3>

The Schwarzschild radius (r) is calculated using:

$r_s = \frac{2GM}{c^2}$

Where:

G = Gravitational constant = 6.67408 × 10-11 m3 kg-1 s-2

M = Mass of the object = 4.6 x 10^6 solar masses

c = Speed of light = 299792458 m / s

Express the mass in Kg

M = 4.6 x 10^6 * 9.2 * 10^18 = 9.15 * 10^36 kg

Substitute the above values in the equation

$r_s = \frac{2 * 6.67408 * 10^{-11} * 9.15 * 10^36}{299792458 ^2}$

Evaluate the expression

$r_s = 13589425339.6$ m

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$r_s = 13589425.3396$ km

Expressas AU

$r_s = \frac{13589425.3396}{1.5 * 10^8}$

Evaluate the quotient

$r_s = 0.09059616893$

Approximate

$r_s = 0.091\ AU$

Hence, the Schwarzschild radius of this supermassive black holeis 0.091 AU

Read more about gravitational radius at:

brainly.com/question/4208016

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2 years ago