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Liula [17]
3 years ago
5

CAN SOMEONE ANSWER ASAP PLEASE!!!!! WILL GIVE EXTRA POINTS

Mathematics
1 answer:
sdas [7]3 years ago
3 0
I'm really sorry if I'm wrong but

14*26=364 so he can go 364 miles for every full tank so his first 364 are covered since he starts with a full tank.

Step 2:
838/26*14 = <span>451
</span>
step 3:


He'd only have to stop once

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Select the locations on the number line to plot the points _2 _11 and _17
bixtya [17]
17 points after 0, 11 points after 0, and 2 points after 0
3 0
3 years ago
Which transformation is not always congruent with its original image
Anika [276]

If they're asking for "congruent" which we know is the shape is the same or equal to. Out of the transformations I assume Dilation because you're altering the size of the shape meaning the image is either bigger than or less than the pre-image. Of course a shape bigger is not equal to the original shape.

think of a king size candy bar to a fun size bar. they're not congruent or the same

5 0
4 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
I need help. I don't understand ​
ycow [4]
Add them all together
5 0
3 years ago
Find the value of x in the triangle shown below​
CaHeK987 [17]

Answer:

<h2>46.4°</h2>

Step-by-step explanation:

Apply sine formula:

\frac{sin \: a}{a}  =  \frac{sin \: b}{b}  =  \frac{sin \: c}{c}

\frac{sin \: a}{a}  =  \frac{sin \: c}{c}

Plug the values

\frac{sin \: (88)}{6.9}  =  \frac{sin \: x}{5}

Apply cross product property

5 \: sin \: (88) = 6.9 \: (sin \: x)

\frac{5 \: sin \: (88)}{6.9}  = sin \: x

x =  {sin}^{ - 1} ( \frac{5 \: sin \:( 88)}{6.9} )

x = 46.4

Hope this helps .....

Best regards!!!

3 0
3 years ago
Read 2 more answers
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