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irakobra [83]
2 years ago
11

What decimal represents the fraction 1/4

Mathematics
2 answers:
Nataly_w [17]2 years ago
8 0

Answer:

0.25.

Step-by-step explanation:

We divide 1 by 4:

4)  1. 00

    0.25

Sedaia [141]2 years ago
3 0

Answer:

0.25

Step-by-step explanation:

1/4 is equal to 1.00 split into 4 equal parts. 0.25*4 = 1.00 , meaning that each 1/4 is equal to 0.25

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What is -4.5= a - 8
murzikaleks [220]

Answer:

Step-by-step explanation: -4.5=a-8

1. add 8 to both sides -4.5+8= 3.5

2. since you added 8 to negative 8 you get zero so it just goes away

3. ANSWER= 3.5=a

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3 years ago
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Determine the quadratic inequality that produces the graph below. HELP ASAP!
svetlana [45]

Answer:

<em> believe it's  option C but not 100 percent sure.</em>

Step-by-step explanation:

I'm not good at explaining.

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2 years ago
Talia is buying beads to make bracelets. She makes a bracelet with 7 plastic beads and 5 metal beads for $7.25. She makes anothe
SVETLANKA909090 [29]
<h2>Plastic Beads = $0.50</h2><h2>Metal Beads = $0.75</h2><h2 />

p = Plastic Beads

m = Metal Beads

Equations:

7p + 5m = 7.25

9p + 3m = 6.75

Make one pair of coefficients the same:

3 * (7p + 5m = 7.25) = 21p + 15m = 21.75

5 * (9p + 3m = 6.75) = 45p + 15m = 33.75

Remove that coefficient;

(45p + 15m) - (21p + 15m) = 33.75 - 21.75

(45p - 21p ) + ( 15m - 15m) = 33.75 - 21.75

24p = 12

24p / 24 = 12 / 24

<h3><u>p = 0.5</u></h3><h3 />

Substitute the result into one of the original equations.

(7 * 0.5) + 5m = 7.25

Rearrange to find the missing value:

7.25 - (7 * 0.5) = 5m

7.25 - 3.5 = 3.75

5m = 3.75

5m / 5 = 3.75 / 5

<h3><u>m = 0.75</u></h3>
3 0
3 years ago
A circular pizza has a diameter 10cm.what is the approximate area of the pizza?(use pi=3)
irina1246 [14]
You would multiply 10 times \pi (3.14)you would multiply 10 times  \pi and get 31.40 cm squared and get 31.40 cm squared
4 0
3 years ago
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Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. What perce
LenKa [72]

Answer:

14.28% of individual adult females have weights between 75 kg and 83 ​kg.

92.82% of the sample means are between 75 kg and 83 ​kg.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that \mu = 79, \sigma = 22.

What percentage of individual adult females have weights between 75 kg and 83 ​kg?

This percentage is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 75. So:

X = 83

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 79}{22}

Z = 0.18

Z = 0.18 has a pvalue of 0.5714.

X = 75

Z = \frac{X - \mu}{\sigma}

Z = \frac{75- 79}{22}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286.

This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 ​kg.

If samples of 100 adult females are randomly selected and the mean weight is computed for each​ sample, what percentage of the sample means are between 75 kg and 83 ​kg?

Now we use the Central Limit THeorem, when n = 100. So s = \frac{22}{\sqrt{100}} = 2.2.

X = 83

Z = \frac{X - \mu}{s}

Z = \frac{83 - 79}{2.2}

Z = 1.8

Z = 1.8 has a pvalue of 0.9641.

X = 75

Z = \frac{X - \mu}{s}

Z = \frac{75-79}{2.2}

Z = -1.8

Z = -1.8 has a pvalue of 0.0359.

This means that 0.9641-0.0359 = 0.9282 = 92.82% of the sample means are between 75 kg and 83 ​kg.

8 0
3 years ago
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