B. 36
<span>Multiply or count branches it's up to you.</span>
Answer: 100, LORD OF MERCY, HOW DO YOU NOT KNOW THIS :sob: anyways if you need more help dm me on discord nishimiya#0001
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Hello,
Roots are -3+2i,-3-2i,-2 and -2
There are 4 roots. (theorem of the conjugate roots) and the least degree of the polynomial is
4.