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anygoal [31]
4 years ago
15

Simplifying by adding, subtracting, multiplying, or dividing: (2/3)-(2/5)

Mathematics
1 answer:
Volgvan4 years ago
8 0
The answer is 4/15 or .26 with the 6 repeating forever.
Explanation: Least common multiple of 3 and 5 is 15. 2*5=10, 2*3=6. 10/15-6/15=4/15.
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Hey can you please help me posted picture of question
liq [111]

B. 36 

<span>Multiply or count branches it's up to you.</span>
4 0
3 years ago
This is hard pls help.
Ksivusya [100]

Answer: 100, LORD OF MERCY, HOW DO YOU NOT KNOW THIS :sob: anyways if you need more help dm me on discord nishimiya#0001

6 0
3 years ago
WORTH 50!! Answer it with explanation and the answer is not y+6 I have some idea on how to do this.
mafiozo [28]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34

Step-by-step explanation:

Given:

2x-3y=12

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

2x-3y=12  

Solution:

2x-3y=12 ...........Given

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx

Where m =slope  

We get

Slope = m1 = \dfrac{2}{3}

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}

Now the equation of line in slope point form given by

(y-y_{1})=m(x-x_{1})

Substituting the point (16 , -7)  and slope m2 we will get the required equation of the line,

(y-7)=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34

6 0
4 years ago
What is the least possible degree of a polynomial that has the root -3 + 2i, and a repeated root -2 that occurs twice?
Anettt [7]
Hello,

Roots are -3+2i,-3-2i,-2 and -2

There are 4 roots. (theorem of the conjugate roots) and the least degree of the polynomial is
4.

4 0
3 years ago
Find the slope of a line parallel to the line through the given points p(-2,4) q(6,-2)
olchik [2.2K]

Answer:

(-2-4)/(6+2)= -6/8= -3/4

8 0
3 years ago
Read 2 more answers
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