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Darina [25.2K]
3 years ago
11

Find an equation for the line below. will give brainiest

Mathematics
1 answer:
pogonyaev3 years ago
8 0

Answer: y=-\frac{x}{2}-6.5

Step-by-step explanation:

First find slope m. From observing the equation we can see that there are two points on the line. They are (-5,-4) and (-1,-6). Using the formula to find slope rise/run we get m = -0.5.

Now we use the point-slope formula to start the switch to the slope-intercept formula. Using (-1,-6) as our x and y values and switching m=-0.5 we get y + 6 = -0.5 ( x + 1). Simplify and we get y + 6 = -x/2 - -0.5. Subtract 6 from both sides and the final equation is y = -x/2 - 6.5.

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F(X) = 1<br> x(x-2)(2x+3)<br> What are the vertical and horizontal asymptotes
Umnica [9.8K]
Y=0




Why?

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes

Hopefully this helped
8 0
3 years ago
Question is attached could you please help me and explain how you got your answer?
vampirchik [111]
Okay so combine like terms
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Now to check:
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3 0
3 years ago
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How do i plot y=0.75x+0.25 on graph
gizmo_the_mogwai [7]
The slope-intercept form is
y
=
m
x
+
b
y
=
m
x
+
b
, where
m
m
is the slope and
b
b
is the y-intercept.
y
=
m
x
+
b
y
=
m
x
+
b
Find the values of
m
m
and
b
b
using the form
y
=
m
x
+
b
y
=
m
x
+
b
.
m
=
0.75
m
=
0.75
b
=
0.25
b
=
0.25
The slope of the line is the value of
m
m
, and the y-intercept is the value of
b
b
.
Slope:
0.75
0.75
Y-Intercept:
0.25
7 0
3 years ago
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adelina 88 [10]

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4 0
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