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ioda
3 years ago
11

A taxi service charges an initial $15 fee, plus $3 per mile driven. A. Write an equation to represent the situation. B. How much

will it cost to travel 45 miles in the taxi?
Mathematics
2 answers:
Paraphin [41]3 years ago
4 0
A. Let x represent the number of miles and y represent the total price.

y=3x+15

B. Using the equation we just wrote, replace the x with 45.

y=3(45)+15


Now multiply 45 by 3.

y=135+15


And finally add together 135 and 15.

y=150

The total cost of a 45 mile taxi ride would be $150.00.
Anastasy [175]3 years ago
4 0
A) you pay $15 no matter what and $3 per mile (which is a rate)
y=3x+15 where x is the amount of miles you drive and y is the total you pay

b) y=3(45)+15 
y= 135 + 15
y= $150
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3 years ago
In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.
Hitman42 [59]

\longmapstoThe value of "x" is 5.

\large\underline{\sf{Solution-}}

Given that,

A trapezium ABCD in which AB || CD such that

  • AO = x - 1

  • CO = BO = x + 1

  • OD = x + 4

Now,

\rm In \: \triangle  \: AOB  \: and \: \triangle \:  COD

\rm  \: \angle  \: AOB  \: and \: \angle \:  COD \:  \:  \{vertically \: opposite \: angles \}

\rm  \: \angle  \:ABO  \: and \: \angle \:  CDO \:  \:  \{alternate \: interior \: angles \}

\bf \: \triangle  \: AOB \:  \sim \:  \triangle  \: COD \:  \:  \:  \{AA \: similarity \}

\bf\longmapsto\:\dfrac{AO}{CO}  = \dfrac{BO}{DO}

\rm \longmapsto\:\dfrac{x - 1}{x + 1}  = \dfrac{x + 1}{x + 4}

\rm \longmapsto\:(x - 1)(x + 4) =  {(x + 1)}^{2}

\rm \longmapsto\: {x}^{2} - x + 4x - 4 =  {x}^{2} + 1 + 2x

\rm \longmapsto\: 3x - 4 =  1 + 2x

\rm \longmapsto\: 3x  -  2x=  1 +4

\bf\longmapsto \:x = 5

7 0
2 years ago
18 - 2x = y
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B. Y equals 0, because if you plug it in ( multiply 2 by 9 ) you will get 18-18 which equals 0.
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3 years ago
To estimate the length of the lake, caleb starts at one end of the lake and walk 95m. He then turns a 60° angle and walks on a n
aivan3 [116]

Answer:

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Step-by-step explanation:

We have given Caleb starts at one end of the lake and walk 95 m

So d_1=95m

And then he turns at an angle of 60°

So \Theta =60^{\circ} and then again walk 8 m

So d_2=8m

We have to fond the total length of the lake , that is d

Total length of the lake is given by d=\sqrt{d_1^2+d_2^2+2d_1d_2cos\Theta }=\sqrt{95^2+8^2+2\times 95\times 8\times cos60^{\circ}}=97.30m

So length of the lake is 97.30 m

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Answer:

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Step-by-step explanation:

if don't know

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