To multiply B and A, the number of columns of B must matc the number of rows of A.
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When we can multiply two matrices?</h3>
When we multiply two matrices, A and B, we multiply the rows of matrix A by the columns of matrix B.
Now, the number of elements in a row of a matrix, is equal to the number of columns (and the number of elements in a column is equal to the number of rows).
To multiply BxA:
Then, a row on matrix B must have the same number of elements than a column in row A.
Then, to multiply BxA, the number of columns of B must match the number of rows of A, meaning that the correct option is the last one.
If you want to learn more about matrices, you can read:
brainly.com/question/11989522
Answer: B.
First, we have to have a question for this problem to create a solution. So, the example sentence is how many granola bars does each student get.
Second, an algebraic expression has a variable in it. So since we are trying to find the number of students, the variable is s.
From looking at C and D, we can already eliminate them. This question has mostly multiplication and division words in it, so it can't be addition and multiplication.
Now, we only have A and B left. A tip on how to figure this out is reading the word problem out thoroughly. I will use B as an example. 5 boxes of granola bars were multiplied by the number of granola bars each student got. From reading this, it makes more sense. But it does change the example sentence, though.
I hope this helped and this is the right answer!
Hello,
if 0 is a positive integer
sum=0+1+...+59=(0+59)*60/2=59*30=1770
else
sum=1+2+3+...+60=(1+60)*60/2=61*30=1830
end if
Answer D: 1830
In US, 0 is not positive, in Europe yes!!!
Answer:
100°
since being sum of angles of triangle
