Question

What is the value of the expression "six less than the quotient of a number and two, increased by 10" when n = 3?

Answer 1

Answer:

$\large\boxed{5\dfrac{1}{2}}$

Step-by-step explanation:

$n-the\ number\\\\\text{the quotient of a number and two}:\ \dfrac{n}{2}\\\\\text{the quotient of a number and two, increased by 10}:\ \dfrac{n}{2}+10\\\\\text{six less than the quotient of a number and two, increased by 10}:\\\\\left(\dfrac{n}{2}+10\right)-6\\\\\text{Put n = 3 to the expression:}\\\\\left(\dfrac{3}{2}+10\right)-6=\left(1\dfrac{1}{2}+10\right)-6=11\dfrac{1}{2}-6=5\dfrac{1}{2}$

Answer 2

Answer: let the number be n

so we have (n/2+10)-6

then we have 11.5-6 which is 5.5.

Step-by-step explanation: