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Ratling [72]
4 years ago
14

a repairman charges an inspection fee plus 20 per hour. A customer with a coupon for 30% off the inspection fee pays $95 for a 3

hour repair. How many hours are worked when a customer pays $130 without a coupon?
Mathematics
2 answers:
charle [14.2K]4 years ago
5 0

Answer:

$108.50 for the 30% off and 1h 35min without the coupon

Step-by-step explanation: 60+95=155

155x0.30=46.5

155-46.5=108.50


pantera1 [17]4 years ago
5 0

Answer:

4.2 hours

Step-by-step explanation:

first you want to find the exact cost of the inspection fee

so you are going to subtract 60 from 95

because if the repair man only worked 3 hours subtracting 60 from 95 will give you the amount they paid minus 30%

add 30% to the 35 and you get 45.5 as the cost of the inspection fee

so subtract 45.5 from 130 and you get 84.5

and now divide 84.5 by 20 aand you have your answer

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The trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ

<h3>How to solve the trigonometric identity?</h3>

Since (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]

Using the identity a² - b² = (a + b)(a - b), we have

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Also, Using the identity a² - b² = (a + b)(a - b), we have

(cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] = (cosθ - sinθ)(cosθ + sinθ)/[(1 - tanθ)(1 + tanθ)sec²θ]

= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)/cosθ × (cosθ + sinθ)/cosθ × sec²θ]

= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)(cosθ + sinθ)/cos²θ × 1/cos²θ]

= (cosθ - sinθ)(cosθ + sinθ)cos⁴θ/[(cosθ - sinθ)(cosθ + sinθ)]

= 1 × cos⁴θ

= cos⁴θ

So, the trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ

Learn more about trigonometric identities here:

brainly.com/question/27990864

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