The mean of the data is 15 all you gotta do is add all the number up and divide by the numbers added
H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
Answer: (3.5,-2)
Step-by-step explanation:
To solve this problem, all we have to do is plug in y=-2 into either equations from step one to find the coordinate. To make sure we have the right x-coordinate, let's plug in y for both equations.
4x-7y=28 [plug in y=-2]
4x-7(-2)=28 [multiply]
4x+14=28 [subtract both sides by 14]
4x=14 [divide both sides by 4]
x=3.5
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6x-5y=31 [plug in y=-2]
6x-5(-2)=31 [multiply]
6x+10=31 [subtract both sides by 10]
6x=21 [divide both sides by 6]
x=3.5
Now, we know the solution to the system is (3.5,-2).
Using substitution:
first you have to express one variable in terms of the other, in this we can express y in terms of x:
Since both expressions are equal to y, you have to equal both expressions like this:
Now you can solve the equation:
Knowing x=10, you can use any of the expressions we found before to find y. In this case I'm going to use y= -x+9 because it's simpler but boy should give you the same result
So, the answer is x=10 and y=-1
Answer:
2.66l
Step-by-step explanation:
hope this will help you
have a great day
