43 points, 86 for brainliest! Answer correct!! Be wise! According to the image attached, whats the answer?

Mathematics

2 answers:

Licemer1 [7]3 years ago

7 0

Answer:

P = 32 in

A = 49 in^2

Step-by-step explanation:

<u>Perimeter</u>

The total horizontal length of the bottom edges is the same as the length of the top edge, so is 8 in. Likewise, the total vertical length of the right edges is the same as the length of the left edge: 8 in. That makes the total length of all edges be 4×8 in = 32 in.

The perimeter is 32 in.

The figure can be decomposed several ways. One of the easiest is to consider it as an 8-inch square with a 3 in by 5 in rectangle removed. Then the area is ...

A = (8 in)^2 -(3 in)(5 in) = (64 -15) in^2

A = 49 in^2

The area is 49 in^2.

Snezhnost [94]3 years ago

6 0

Answer:

$p = 32\: \: in$

$a = 49 {in}^{2}$

Step-by-step explanation:

$perimeter \\ = 8 + 8+8+8 \\ = 32 \: \: in$

$area \\ 1)3 \times 8 = 24 \\ 2)5 \times 5 = 25 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 49 {in}^{2}$

hope this helps

brainliest appreciated

good luck! have a nice day!

You might be interested in

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap

11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=20$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20$

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

$h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)$