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rjkz [21]
3 years ago
10

Does the associative property always, sometimes, or never hold for subtraction. Explain your reasoning using examples and non-ex

amples! please help!
Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer: You should remember that if the minus sign is before the parentheses, you need to distribute it, otherwise, you can always use it.

Step-by-step explanation:

The associative property says that:

A + (B + C) = (A + B) + C  

Where A, B, and C are real numbers.

Let's see if it does:

10 + (- 5 - 4) = 10 + (-9) = 1

(10 + -(5)) - 4 = 5 - 4 = 1

thiw seems to work, let's se other case:

10 - (5 - 4) = 10 - (1) = 9

now, apply the associative relation

(10 -5) + 4 = 9

Where the sign must change, because we actually have that -(5 - 4) = -1*(5 - 4) so we must distribute the minus sign in the parentheses.

Then, if you take this in mind, you always can use the associative property.

ollegr [7]3 years ago
6 0
The associative property never works with subtraction.

For example:
2 - (7-8) <span>≠ (2-7) - 8
2-(-1)=3, but (-5)-8=-13
</span>
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Help with this short answer.
timurjin [86]

Start by solving inside the parentheses. According to PEMDAS you will divide 10 and 2 first. Divide 10 by 2 and you will have: 8 + (5)(4) - (6 + 5) + 44.

Now finish solving inside the parentheses and add 6 and 5.

8 + (5)(4) - (11) + 44, multiply 5 and 4.

8 + 20 - 11 + 44, then solve from left to right.

61 is the answer.

8 0
4 years ago
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Given the expression below, which statement is true about the
artcher [175]

Answer:

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3 0
3 years ago
X + 128 = x + 68 find x
mixas84 [53]

Answer:

no \: solution

Step-by-step explanation:

1) Cancle x from both sides.

128 = 68

2) Since 128 = 68 is false, There is no solution.

no \: solution

8 0
3 years ago
Suppose that you had two squares, a small one and a large one. The area of the large square is twice that of the small square. H
WARRIOR [948]

Answer:

The side length of the large square is √2 times larger than the side length of the small square.

Step-by-step explanation:

Suppose we have a small square (square 1) and a large square (square 2). The area of the large square is twice that of the small square, that is,

A₂ = 2 A₁

A₂/A₁ = 2 [1]

The area of a square is equal to the length of the side (l) raised to the second power.

A = l²

l = √A

The ratio of l₂ to l₁ is:

l₂/l₁ = √A₂ / √A₁ = √(A₂/A₁)

We can replace [1] in the previous expression.

l₂/l₁ = √2

The side length of the large square is √2 times larger than the side length of the small square.

7 0
3 years ago
Can someone please help me with this question? From question A through to question d. Thank you
Alexandra [31]
I can only help with d... the answer is 38.
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3 years ago
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