I found this on another question made before
Answer:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
T = (forAB2C + 9forBC)
T = (forAB2C + 9forBC)
Solving
T = forAB2C + 9forBC
Solving for variable 'T'.
Move all terms containing T to the left, all other terms to the right.
Simplifying
T = forAB2C + 9forBC
Step-by-step explanation:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
Answer:
2, 4 ,6 8
Step-by-step explanation:
Given condition y = 2x
When x = 1 , y = 2 *1 = 2
When x = 2 , y = 2 * 2= 4
when x = 3 , y = 2* 3 = 6
When x = 4 , y = 2 * 4 = 8
Hope it will help :)
ededededededededededededededededdedededededededededededededededededededededededededededededededededededededededededededededededededededededddeeedddeeedddeeedddeeeddd-------------------------------------------------------------------------------------------------------------------------------------------------------
Answer:

Step-by-step explanation:
The question we have at hand is, in other words,
- where we have to solve for the value of 
If we have to isolate
here, then we would have to take the inverse of the following matrix ...
... so that it should be as follows ... 
Therefore, we can conclude that the equation as to solve for "
" will be the following,
- First find the 2 x 2 matrix inverse of the first portion,
=
=
=
At this point we have to multiply the rows of the first matrix by the rows of the second matrix,
,
- Simplifying this, we should get ...
... which is our solution.