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inysia [295]
3 years ago
11

What can be made in a cube and not a pyramid? A hexegon, triangle or a square? Please answer thank you!

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:

It's a square.

Step-by-step explanation:

geniusboy [140]3 years ago
4 0

Answer:

A square

Step-by-step explanation:

I'm pretty sure its a square

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The radius r of a sphere is 12 units. Find the volume of the sphere. Write your answer in terms of pie
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https://socratic.org/questions/what-is-the-volume-of-a-sphere-with-a-radius-of-12-units

the answer is on here

6 0
3 years ago
If(X+1)and(3x+2)are factors of 3x^3+2x^2-3x-2, find the third factor​
Lelechka [254]

Answer:

3  {x}^{3}  + 2 {x}^{2}  - 3x - 2 =  \\  {x}^{2} (3x + 2) - 1 \times (3x + 2) =  \\ (3x + 2)( {x}^{2}  - 1) = (3x + 2)(x - 1)(x + 1)

6 0
2 years ago
Find the common difference of the sequence shown 1/6,1/3,1/2,2/3,......
tekilochka [14]

Answer:

Common Difference(d) is    

               d=\frac{1}{6}

Step-by-step explanation:

Given sequence is :

                 \frac{1}{6}, \frac{1}{3} ,\frac{1}{2} ,\frac{2}{3} .........

If a sequence has a constant common difference throughout the sequence, then the sequence is called Arithmetic Progression.

Considering a sequence:

       a_1,a_2,a_3,a_4..........\\

a_2-a_1=a_3-a_2=a_4-a_3=a_n-a_n_-_1=d

where 'd' is the common difference of the A.P.

Similarly, finding the common difference of the given sequence.

       

                           \frac{1}{3} -\frac{1}{6}= \frac{1}{2}- \frac{1}{3}=\frac{2}{3} - \frac{1}{2}=d\\

                              d=\frac{1}{3}-\frac{1}{6}=\frac{(2)(1)-(1)(1)}{6}=\frac{1}{6}

                                   d=\frac{1}{6}

Common Difference(d) is    

               d=\frac{1}{6}

8 0
3 years ago
Read 2 more answers
What are the main units of length. in the US
zzz [600]
The main units are inches, centimeters, meters, feet, and yards.
7 0
3 years ago
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A set of equations is given below:
Zanzabum
The answer is:  [A]:  "No solution" .
_______________________________________________
Note:  Given:
_______________________________________________
  y = 4x + 8 ;
  y = 4x + 2 ;
_______________________________________________

Since:  "y = y" ;

4x + 8 = 4x + 2 ; which is not true;
______________________________
 4x  +  8  ≠  4x  +  2 ;  since,  "8  ≠ 2" ;

Note:  Suppose:  "4x + 8 = 4x + 2" ; 

→ Subtract "4x" from each side of the equation:

4x + 8 − 4x  = 4x + 2 − 4x ;

to get:
_________________
 " 8 = 2 " ;  not true ; since  "8 ≠ 2" ;
______________________________
Also, suppose:
_______________________________
 4x + 8 = 4x + 2 ;

→ Subtract "2" from BOTH SIDES of the equation;

4x + 8 − 2 = 4x + 2 − 2 ;

to get:

4x + 6 = 4x

(Note:  "4x + 0 = 4x" ;  but "4x + 6 ≠ 4x") l

But even if we have:

4x + 6 = 4x ;

→ Subtract "4x" from EACH side of the equation:

4x + 6 − 4x  = 4x − 4x ;

to get:

   6 = 0 ; which is not true;  "6 ≠ 0" . 
____________________________________
The correct answer is:  [A]:  "No solution" .
______________________________________

4 0
3 years ago
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