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jek_recluse [69]
3 years ago
7

Find the common difference in the arithmethic sequence 3 ,13/4 ,7/2 , 15/4

Mathematics
1 answer:
EleoNora [17]3 years ago
6 0
13/4-3=13/4-12/4
=1/4
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7) d)

standard error of the mean of one sample of 'n' observation = 0.20

8) a)

The margin of Error = 0.392

9) d

The 95% of confidence intervals are (8.61 , 9.39)

Step-by-step explanation:

7)

solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

The standard error of the mean of one sample of 'n' observation is

Standard error (SE)

                               = \frac{S.D}{\sqrt{n} }  

                               = σ / √n

                               = \frac{1.8}{\sqrt{81} } =0.2

standard error of the mean of one sample of 'n' observation = 0.20

8)

Solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

Given the probability is 0.95

The z- score = 1.96 at 0.05 level of significance.

The margin of Error   =  \frac{z_{0.95} S.D}{\sqrt{n} }

                                   = \frac{1.96 (S.D)}{\sqrt{n} }

                                   = \frac{1.96 (1.8)}{\sqrt{81} }

                                   = 0.392

The margin of Error = 0.392

9)

Solution:-

<u>The 95% of confidence intervals are </u>

<u></u>(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96\frac{S.D}{\sqrt{n} } )<u></u>

<u></u>(9 - 1.96\frac{1.8}{\sqrt{81} } , 9+ 1.96\frac{1.8}{\sqrt{81} } )<u></u>

(9 - 0.392 , (9 + 0.392)

(8.609 , 9.392)

<u>The 95% of confidence intervals are </u>(8.61 , 9.39)

 

4 0
3 years ago
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