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kodGreya [7K]
3 years ago
15

How do you graph y+2=-2(x – 4) ?

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Explanation:

Start out by using the Distributive Property to convert from <em>Point-Slope Form</em> to <em>Slope-Intercept Form</em>:

y + 2 = −2x + 8

- 2 - 2

______________

\displaystyle y = -2x + 6

Now, starting from the y-intercept of [0, 6], you do \displaystyle \frac{rise}{run}by either moving two blocks <em>north</em><em> </em>over one block <em>west</em> or two blocks <em>south</em><em> </em>over one block <em>east</em> [<em>west</em> and <em>south</em> are negatives].

I am joyous to assist you anytime.

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If tan theta = 10/13 and cos theta &gt; 0 then sin2theta is what ?
svetoff [14.1K]

sin2\alpha  = \frac{260}{269}

<u>Step-by-step explanation:</u>

We have , Tan\alpha  = \frac{Perpendicular}{Base} = \frac{10}{13},

We know that sin\alpha  = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }

Substituting values of P & B , sin\alpha  = \frac{10}{\sqrt{10^{2} + 13^{2}} }  = \frac{10}{\sqrt{269} }

Now , sin2\alpha  = 2sin\alpha cos\alpha  = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }

⇒sin2\alpha  = \frac{10}{\sqrt{269} } ×\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }×2

⇒ sin2\alpha  = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} }  )

⇒sin2\alpha  = \frac{20}{\sqrt{269} }( \sqrt{\frac{169 }{269} }  )

⇒sin2\alpha  = \frac{260}{\sqrt{269} }( \sqrt{\frac{1}{269} }  )

⇒sin2\alpha  = \frac{260}{269}

6 0
3 years ago
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kaheart [24]

Answer:

b

Step-by-step explanation:

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4 0
3 years ago
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Answer:

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3 years ago
Help plsss<br> Find Perimeter
Keith_Richards [23]

Answer:

Step-by-step explanation:

10+10=20

8+8 = 16

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8 x 3.14 = 25.12 but your not done yet its a half circle so divide by 2

25.12/2 = 12.56

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lora16 [44]
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3 years ago
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