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andreyandreev [35.5K]
3 years ago
7

Which of the following is TRUE about a TCF Free Student Checking Account?

Mathematics
2 answers:
Lerok [7]3 years ago
7 0

Answer:

Step-by-step explanation:

If the answer choices are:

A. minimum deposit to open is $25

B. Monthly maintenance fee is $15 dollars per month

C. The account earns interest, which makes it a good savings account too

D. There is a $3 withdrawal fee for using an ATM in the TFC ATM network

The answer is most likely A

Fiesta28 [93]3 years ago
4 0

Answer: What Of The Following? Please Put A Picture Or Make Sure You Don't forget anything in your'e question.

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The beginning balance in the computers account was $2000.the company purchased an additional $1000 worth of computers.the balanc
Amanda [17]
D. Debit of $3000
The balance of account a need to be as much as $3000
7 0
4 years ago
A total of 2n cards, of which 2 are aces, are to be randomly divided among two players, with each player receiving n cards. Each
klasskru [66]

Answer:

P(X_s^c|X_F) =0.2

P(X_s^c|X_F) =0.31

P(X_s^c|X_F) =0.331

Step-by-step explanation:

From the given information:

Let represent X_F as the first player getting an ace

Let X_S to be the second player getting an ace and

\sim X_S as the second player not getting an ace.

So;

The probabiility of the second player not getting an ace  and the first player getting an ace can be computed as;

P(\sim X_S| X_F) = 1 - P(X_S|X_F)

P(X_S|X_F) = \dfrac{P(X_SX_F)}{P(X_F)}

Let's determine the probability of getting an ace in the first player

i.e

P(X_F) = 1 - P(X_F^c)

= 1 -\dfrac{(^{2n-2}_n)}{(^{2n}_n)}}

= 1 - \dfrac{n-1}{2(2n-1)}

=  \dfrac{3n-1}{4n-2} --- (1)

To determine the probability of the second player getting an ace and the first player getting an ace.

P(X_sX_F) = \text{ (distribute aces to both ) and (select the left over n-1 cards from 2n-2 cards}P(X_sX_F) = \dfrac{2(^{2n-2}C_{n-1})}{^{2n}C_n}

P(X_sX_F) = \dfrac{n}{2n -1}---(2)

P(X_s|X_F) = \dfrac{2}{1}

P(X_s|X_F) = \dfrac{2n}{3n -1}

Thus, the conditional probability that the second player has no aces, provided that the first player declares affirmative is:

P(X_s^c|X_F) = 1- \dfrac{2n}{3n -1}

P(X_s^c|X_F) = \dfrac{n-1}{3n -1}

Therefore;

for n= 2

P(X_s^c|X_F) = \dfrac{2-1}{3(2) -1}

P(X_s^c|X_F) = \dfrac{1}{6 -1}

P(X_s^c|X_F) = \dfrac{1}{5}

P(X_s^c|X_F) =0.2

for n= 10

P(X_s^c|X_F) = \dfrac{10-1}{3(10) -1}

P(X_s^c|X_F) = \dfrac{9}{30 -1}

P(X_s^c|X_F) = \dfrac{9}{29}

P(X_s^c|X_F) =0.31

for n = 100

P(X_s^c|X_F) = \dfrac{100-1}{3(100) -1}

P(X_s^c|X_F) = \dfrac{99}{300 -1}

P(X_s^c|X_F) = \dfrac{99}{299}

P(X_s^c|X_F) =0.331

8 0
3 years ago
Is DEF a right triangle? True or false
umka2103 [35]
Short answer = false
Remark

If it is a right triangle, it will obey the Pythagorean Equation. a^2 + b^2 = c^2. Let's see if it does.

Equation
a^2 + b^2= c^2
c must be the longest line. (Hypotenuse)

Givens
a = 24
b = 17
c = 40

Sub and Solve
a^2 + b^2 = c^2
17^2 + 24^2 = c^2 [We'll see if this comes out to 40]

289 + 576 = c^2
865 = c^2 which is no where near what 40^2 equals. 40^2 = 1600

Short answer False

Square root of 865 = (865)^1/2 = 29.4
5 0
4 years ago
Write a compound inequality that the graph could represent.
Free_Kalibri [48]
The answer is B!
I could explain further if needed!
6 0
3 years ago
What is the solution to the equation 12(x+5)=4x
lubasha [3.4K]

Answer:

-15/2 =x

Step-by-step explanation:

12(x+5)=4x

Distribute

12x +60 = 4x

Subtract 12x from each side

12x-12x +60 = 4x-12x

60 = -8x

Divide each side by -8

60/-8 = -8x/-8

15/-2 = x

-15/2 =x

5 0
3 years ago
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