Question

Find an equation for these points (-5,5) (4,2)

Answer 1

Answer:

$\large\boxed{y=-\dfrac{1}{3}x+\dfrac{10}{3}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (-5, 5) and (4, 2).

substitute:

$m=\dfrac{2-5}{4-(-5)}=\dfrac{-3}{9}=-\dfrac{1}{3}$

Put the value os a slope and coordinates of the point (4, 2) to the equation of a line:

$2=-\dfrac{1}{3}(4)+b$

$2=-\dfrac{4}{3}+b$             add 4/3 to both sides

$2\dfrac{4}{3}=b\to b=3\dfrac{1}{3}\to b=\dfrac{10}{3}$