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3 years ago

10

Drag each number to the correct location in the ordered pairs. Each number can be used more than once, but not all numbers will

be used. Point A is located at (7, 4). Point A is reflected across the x-axis to give point B. Point B is reflected across the y-axis to give point C. Drag numbers to show the correct coordinate pairs for point B and point C. 7 0 -4 -3 -7 4 3

1 answer:

marishachu [46]3 years ago

4 0

Answer:what?

Step-by-step explanation:

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(x+1)^2+(x-1)^2-2x(x+2)=0

antoniya [11.8K]

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

$(x+1)^2+(x-1)^2-2x(x+2)=0$
$x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0$
$(x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0$
$-4x + 2 = 0$

Step 2: Subtract 2 from both sides.

$-4x + 2 - 2 = 0 - 2$
$-4x = -2$

Step 3: Divide both sides by -4.

$\frac{-4x}{-4} = \frac{-2}{-4}$
$x = \frac{1}{2}$

8 0

2 years ago

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of <em>X</em> as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago

Can someone please help me

Vsevolod [243]

The restrictions for the equation is that the denominator can not be zero. So the restrictions for x would be what values make the denominator zero.

7x^2 + 6x = 0
factor
x(7x + 6) = 0
multiply any number by 0 and you get 0. So either x = 0 or 7x+6 = 0
since there's a x in the numerator x/x = 1 so this will not be a restriction. Then the only restriction is:
7x+6 = 0
7x = -6
x = -6/7

5 0

3 years ago

2x squared - 3x = 2x - 2

elena-s [515]

Answer: x=1/2 or x=2

4 0

3 years ago

Read 2 more answers

HELP ME PLZZZZZZZZZZZZZZZz<br> 3a+5+8

ivann1987 [24]

Answer: I believe your answer is 17.

Step-by-step explanation: 3a+5+8

Since there is only one a you can turn the a into a 1. So it’s now 3+1+5+8=17 it’s either that or it’s 3x1+5+8= 16

So your answer is either 16 or 17 I believe. Hope I helped!

3 0

3 years ago

Read 2 more answers