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Nikolay [14]
3 years ago
7

Find the perimeter of the rectangle with points... W(6,9), X(9,7), Y(3,-2), Z(0,0)

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0
Find the perimeter of the rectangle with points...
W(6,9), X(9,7), Y(3,-2), Z(0,0)

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Z-m=z+bx , solve for b
KIM [24]

Answer:

b= (Z-m-z)/(x)

Step-by-step explanation:

Z-m=z+bx

Z-m-z=bx [Transpose z of R.H.S to L.H.S] / [Substract z from L.H.S and R.H.S]

(Z-m-z)/(x)=b [Divide by x on both sides i.e, L.H.S and R.H.S]

b= (Z-m-z)/(x)

Hope this helps you.

3 0
3 years ago
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Please help me please thank you
AleksandrR [38]

Answer:

x = 15

Step-by-step explanation:

angles 2 and 4 are supplementary so they add up to 180

2x + 10 + 4x + 80 = 180

6x + 90 = 180

6x = 90

x = 15

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3 years ago
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Explain how you can use a basic subtraction fact to help you solve 98-30.
solniwko [45]
You do what I’d 9-3 , 8-0 , then combined it and you will get the right answer
6 0
3 years ago
Given parallelogram ABCD , diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8 . Find the length of AC
Crank

Answer:

I think the answer shod be B

3 0
3 years ago
A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?
slavikrds [6]

Answer:

P(Woman) = \frac{23}{106}

Step-by-step explanation:

Given

Women = 23

Men = 83

Required

P(Woman)

This is calculated as the number of women divided by the population of the class

i.e.

P(Woman) = \frac{Women}{Women + Men}

So, we have:

P(Woman) = \frac{23}{23+83}

P(Woman) = \frac{23}{106}

7 0
3 years ago
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