Permutation: In a race of 10 students, find the number of ways students can finish 1st, 2nd, and 3rd. In this case the order matters, so it is a permutation.
10 x 9 x 8 = 720 ways
Combination: In a class of 10 students, find the number of ways a group of 3 students can be selected to win a prize. In this case the order doesn't matter, so it's a combination.
10 x 9 x 8 / (3 x 2 x 1) = 120 ways
Answer:
2/27
Step-by-step explanation:
5/12×8/45 divide using the common factor of 5and 45 which is 5 and common factor of 8and 12 is 4
The answer is 4100 hope it helped
