Answer:
No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.
Example:
the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.
10 + 79 + 42 + 88 + 19 + 50 = 288
288 ÷ 6 = 48
Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.
<h3>
What are extraneous solutions?</h3>
Your information is incomplete. Therefore, an overview will be given. An extraneous solution is the root of a transformed equation which is not a root of the original equation since it was excluded from the domain of the original equation.
The reason extraneous solutions exist is simply that some operations produce extra answers, and these operations are a part of the path to solving the problem.
Learn more about equations on:
brainly.com/question/2972832
Think of it this way: Lets add numbers in pairs, starting at the very outer 2 numbers (19 and 77) then go in by one and add the second number and the second to last (20 and 76), then (21 and 75) and so on. The sum of all of these pairs are all the same: 96. How many 96s will we have? Well since we're coming from each end toward the middle adding pairs we will have half the distance between 19 and 77, that is (77-19)/2 = 29. So we can actually just take 96*29 = 2784. This is the sum of all numbers between 19 and 77
Answer: 1000000
Step-by-step explanation:
5x100
Answer:
1:
we have a rule that is (n-2)×180
while n = number of sides
2:
exterior angle of a polygon = 360 ÷ number of sides
so 360÷25=14.4
3:
octagon is 8 side, so as we said: (8-2)×180 = 1080
4:
lets make an equation, we know that (n-2)×180 = the sum
so (x-2)×180=720
180x -360 = 720
180x = 1080
x=6
