<span>h = –16t 2 + 64t + 8
since both the launch height and target height are identical we can say height is 0
solve for t
0 = -16t^2 + 64t +8
-8(2t^2-8t-1) =0
divide both sides by -8
2t^2-8t -1 = 0
t = 4.12 and -0.121
since it can't be a negative number:
t = 4.12 seconds ( round off as needed)
</span>
Answer:
A
Step-by-step explanation:
Angle QSR is 180° - 150°, is 30°
So basically you're getting the answer for tan30° which is 
A’=(1,.5) you just multiply the points by whatever the dilation is, so by .5