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den301095 [7]
3 years ago
13

What is the converse of the statement “If an angle has a bisector, then it is cut in half”?

Mathematics
1 answer:
Nitella [24]3 years ago
6 0
Converse....switch the hypothesis and conclusion

ur converse is : If an angle is cut in half, then it has a bisector
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Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0
3 years ago
Solve the system using substitution y=2x+10 y=x+8
kvv77 [185]

Answer:

x = -2

Step-by-step explanation:

x+8 = 2x +10

-2x + x = 10-8

-x = 2

divide both side by -1

answer -- x = -2

8 0
3 years ago
M
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Answer:

0

Step-by-step explanation:

4 0
4 years ago
Describe the transformation of f(x)=x^3 to g (x)=-4 (x-1)^3+7
evablogger [386]

Answer:

ill help

Step-by-step explanation:

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3 years ago
Write an equation for the line parallel to the line 5/8x−7/6y =2 through the point (7,−1).
LiRa [457]

y =  -  \frac{28}{48x - 15} -  \frac{125}{321}is the answer.

Step-by-step explanation:

For this question,

•<u> </u><u>First</u>, find the slope of the line parallel to the line 5/8x−7/6y=2 :-

m =  - \frac{28}{ - 15 + 48x}

•<u>Second</u>, find the equation of the line,

y =  -  \frac{28}{48x - 15} -  \frac{125}{321}

7 0
2 years ago
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