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3 years ago

5

In number 8 the options are

2 answers:

Tresset [83]3 years ago

7 0

9) is 180-(67+28)=85 because a triangle will always equal 180 degrees you take the other two add them together and subtract them from 180.

10) A flat line is 180 degrees and if a line cuts through two perpendicular lines it will bisect at the same angle. so 180-125=x=55 degrees

jeka943 years ago

3 0

I think the answer is c

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Sarah bikes for 15 minutes last week. Jennie biked for 89 minutes last week. How many minutes did the girls bike

exis [7]

104 minutes all You have to do is add them both together

6 0

3 years ago

Read 2 more answers

Use either the substitution or elimination method to solve the following word problem. Your answer should include two equations

vichka [17]

Let w represent the number of weeks passed.

The amount of money Ed saved is 6w - 1 (I'm subtracting the one dollar that he owes to someone)

His sister saved 6w + 2.66 (I'm adding the money she already saved).

What value of w makes both expressions equal?
We need to solve the equation 6w - 1 = 6w + 2.66

Let's solve it.
If we subtract 6w from both sides, we get -1 = 2.66
So, there is no solution. They will never have saved the same amount.
This makes sense because they started out with different amounts of money saved, but they are saving at the same rate.

7 0

4 years ago

Read 2 more answers

19) Albert says that the two systems of equations shown have the same solutions.

k0ka [10]

Answer:

option A) Agree, because the solutions are the same is correct.

Step-by-step explanation:

FIRST SYSTEM

$6x + y= 2$

$-x-y=-3$

solving the system

$\begin{bmatrix}6x+y=2\\ -x-y=-3\end{bmatrix}$

$\mathrm{Multiply\:}-x-y=-3\mathrm{\:by\:}6\:\mathrm{:}\:\quad \:-6x-6y=-18$

$\begin{bmatrix}6x+y=2\\ -6x-6y=-18\end{bmatrix}$

adding the equation

$-6x-6y=-18$

$+$

$\underline{6x+y=2}$

$-5y=-16$

so the system becomes

$\begin{bmatrix}6x+y=2\\ -5y=-16\end{bmatrix}$

solve -5y for y

$-5y=-16$

Divide both sides by -5

$\frac{-5y}{-5}=\frac{-16}{-5}$

simplify

$y=\frac{16}{5}$

$\mathrm{For\:}6x+y=2\mathrm{\:plug\:in\:}y=\frac{16}{5}$

$6x+\frac{16}{5}=2$

subtract 16/5 from both sides

$6x+\frac{16}{5}-\frac{16}{5}=2-\frac{16}{5}$

$6x=-\frac{6}{5}$

Divide both sides by 6

$\frac{6x}{6}=\frac{-\frac{6}{5}}{6}$

$x=-\frac{1}{5}$

Therefore, the solution to the FIRST SYSTEM is:

$x=-\frac{1}{5},\:y=\frac{16}{5}$

SECOND SYSTEM

$2x-3y = -10$

$-x-y=-3$

solving the system

$\begin{bmatrix}2x-3y=-10\\ -x-y=-3\end{bmatrix}$

$\mathrm{Multiply\:}-x-y=-3\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y=-6$

$\begin{bmatrix}2x-3y=-10\\ -2x-2y=-6\end{bmatrix}$

$-2x-2y=-6$

$+$

$\underline{2x-3y=-10}$

$-5y=-16$

so the system of equations becomes

$\begin{bmatrix}2x-3y=-10\\ -5y=-16\end{bmatrix}$

solve -5y for y

$-5y=-16$

Divide both sides by -5

$\frac{-5y}{-5}=\frac{-16}{-5}$

Simplify

$y=\frac{16}{5}$

$\mathrm{For\:}2x-3y=-10\mathrm{\:plug\:in\:}y=\frac{16}{5}$

$2x-3\cdot \frac{16}{5}=-10$

$2x=-\frac{2}{5}$

Divide both sides by 2

$\frac{2x}{2}=\frac{-\frac{2}{5}}{2}$

Simplify

$x=-\frac{1}{5}$

Therefore, the solution to the SECOND SYSTEM is:

$x=-\frac{1}{5},\:y=\frac{16}{5}$

Conclusion:

As both systems of equations have the same solution.

Therefore, we conclude that Albert is right when says that the two systems of equations shown have the same solutions.

Hence, option A) Agree, because the solutions are the same is correct.

8 0

3 years ago

Help please will give brainliest

nataly862011 [7]

Answer:

B

Step-by-step explanation:

4x12=48/2x2=B or 48

7 0

3 years ago

Read 2 more answers

3у(6у+2х)-(х+3у)^2 при х=√2 , у=√7 <br><br> 4ab/+4b*(a/4b-4b/a) при a=4√5+3,b=√5-9

kompoz [17]

$\pi$ is the answer.

5 0

4 years ago