Question

PLEASE HELP!!

Answer 1

Answers:

• Problem 5)   x = 4
• Problem 6)   y = 8
• Problem 7)   z = 4

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Explanations:

Problem 5)

Assuming HEFG is a parallelogram, this means the opposite sides are the same length.

EH = GF

x-3 = 4x-15

x-4x = -15+3

-3x = -12

x = -12/(-3)

x = 4

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Problem 6)

We'll use the same idea from problem 5. The opposite sides EF and HG are congruent

EF = HG

3y = 3x+12

3y = 3*4+12

3y = 24

y = 24/3

y = 8

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Problem 7)

For any parallelogram, the diagonals always cut each other in half.

Therefore HK = 2z+3 is exactly half that of segment HF = 22

Put another way, HF is twice as long as HK

2*(HK) = HF

2*(2z+3) = 22

4z+6 = 22

4z = 22-6

4z = 16

z = 16/4

z = 4