Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.
Indeed, those two numbers are relatively prime.
Answer:
sorry if im wrong i think wrong numbers. plz check
Step-by-step explanation:
The center of dilation of the question is (-4,-3) .
let say that
x0=-4
y0=-3
Label the image A'B'C'
The new coordinate would be
A(-4,-1)
x=4
y=-1
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-1 +3)
y'=-3 +4= 1
______________________________
B(-4,-3)
x=-4
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
______________________________
C(-1,-3)
x=-1
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-1 +4)
x'=-4 +6= 2
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
A'(-4,1)
B'(-4,-3)
C'(2,-3)
Answer: the first one :x=y+
−19
/8
the second one: x=y−2
Step-by-step explanation:
9 and 10
11 and 12
13 and 14
15 and 16
the square root of 125 is 11.18 so therefore it falls between 11 and 12
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