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monitta
2 years ago
9

Hiked 3 5/6 miles and 2 1/2 miles on Saturday. Hiked 1 1/3 miles on Sunday. How many more miles to hike for a 10 mile hike

Mathematics
1 answer:
Lina20 [59]2 years ago
4 0

Answer:

I dont really know

Step-by-step explanation:

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Aiden borrows a book a public library. He read a few pages on day one. One day two, he reads twice the number of pages than he r
Alisiya [41]

Answer:

110 pages

Step-by-step explanation:

Day 1 =x

Day 2 =2x

Day 3 =x-6

(x)+(2x)+(x-6)=458

Add likes together.

4x-6=458

4x=464.  Divide both sides by 4 to get x. X=116

Day 3=116-6=110

7 0
3 years ago
Last year Salma opened an investment account with $8200. At the end of the year the amount in the account had increased by 6.5%.
nikklg [1K]

Answer:

61,500

Step-by-step explanation:

8200 x 6.5 = 53,300 + 8200 = 61,500 = $61,500

3 0
3 years ago
Martha states that –6 is a rational number. Which is a correct explanation for this statement?
bonufazy [111]

Answer:

Step-by-step explanation:

-6 is rational because it can be written as a ratio -6/1 for example

6 0
3 years ago
Read 2 more answers
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
If officer brimberry wrote 16 tickets for traffic violations last week but only 10 tickets this week what is the percent decreas
melamori03 [73]
I believe this is right..

10/16= x/100
x=62.5%
100%- 62.5%= 37.5%
5 0
3 years ago
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