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zaharov [31]
3 years ago
15

Brent purchased a used vehicle that depreciates under a straight-line method. The initial value of the car is $7500, and the sal

vage value is $500. If the car is expected to have a useful life of another 7 years, how much will it depreciate each year?
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
Let the value of the vehicle be described by the equation
V = a + bx
where x =  number of years since purchase
a,b are constants.

When x = 0, V = $7500. Therefore
a + b*0 = 7500
a = 7500

When x = 7, V = $500. Therefore
7500 + 7b = 500
7b = 500 -7500 = -7000
b = -7000/7 = -1000

The equation is
V = 7500 - 1000x

The slope of this equation is the depreciation rate, and it is -$1000 per year.

Answer: $1000 depreciation per year.

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Answer:

y = 3/2x+6

Step-by-step explanation:

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A tester sets 99% confidence limits on a certain statistic. The absolute difference between either limit and the mean is an exam
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the margin of error
the variance
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Select the correct answer, and simplify the expression -3÷(-2/5). A. -7 1/2
aliina [53]

Answer:

D

Step-by-step explanation:

Given

- 3 ÷ - \frac{2}{5}

Leave the first number, change division to multiplication and turn the fraction upside down, that is

= - 3 × - \frac{5}{2}

= \frac{3(5)}{2}

= \frac{15}{2}

= 7 \frac{1}{2} → D

3 0
3 years ago
How do I solve for the fourth term in this sequence?
tatiyna

Answer:

<h2>d(4) = 64</h2>

Step-by-step explanation:

d(1) = 13

d(n) = d(n - 1) + 17

where

n is the nth term

To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term

So we have

<u>For the 2nd term</u>

That's d(2)

We have

d(2) = d(2-1) + 17

d(2) = d(1) + 17

But d(1) = 13

d(2) = 13 + 17 = 30

<u>For the 3rd term d(3)</u>

That's

d(3) = d(3 - 1) + 17

d(3) = d(2) + 17

d(3) = 30 + 17 = 47

<u>For the 4th term that's d(4)</u>

We have

d(4) = d(4 - 1) + 17

d(4) = d(3) + 17

d(4) = 47 + 17

We have the final answer as

<h3>d(4) = 64</h3>

Hope this helps you

3 0
3 years ago
Help please!!!!!!!!!!!!!!!
anygoal [31]
-1. hope that helps!
3 0
3 years ago
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