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zysi [14]
3 years ago
12

Which statement is true of triangles FGH and JKL?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

im pretty sure its B

Step-by-step explanation:

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Brittany has a recipe which yields 25 hamburgers, but she only needs to make 10. If the original recipe calls for nine pounds of
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Simplify the square root.<br> 6-63
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Answer:

18i\sqrt{x} 7\\

Step-by-step explanation:

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2 years ago
he radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had lost
elena-s [515]

Answer:

The bones were 12,485 years old at the time they were​ discovered.

Step-by-step explanation:

Amount of the element:

The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The radioactive element​ carbon-14 has a​ half-life of 5750 years.

This means that A(5750) = 0.5A(0), and we use this to find k. So

A(t) = A(0)e^{-kt}

0.5A(0) = A(0)e^{-5750k}

e^{-5750k} = 0.5

\ln{e^{-5750k}} = \ln{0.5}

-5750k = \ln{0.5}

k = -\frac{\ln{0.5}}{5750}

k = 0.00012054733

So

A(t) = A(0)e^{-0.00012054733t}

A scientist determined that the bones from a mastodon had lost 77.8 ​% of their​ carbon-14. How old were the bones at the time they were​ discovered?

Had 100 - 77.8 = 22.2% remaining, so this is t for which:

A(t) = 0.222A(0)

Then

0.222A(0) = A(0)e^{-0.00012054733t}

e^{-0.00012054733t} = 0.222

\ln{e^{-0.00012054733t}} = \ln{0.222}

-0.00012054733t = \ln{0.222}

t = -\frac{\ln{0.222}}{0.00012054733}

t = 12485

The bones were 12,485 years old at the time they were​ discovered.

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3 years ago
Explain what the slope of a linear relationship is.
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The slope is the same as rate of change. In a linear graph, it is the change in y over the change in x.
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3 years ago
Writing in Slope-Intercept Form, 4 Ways (3, 2) &amp; (-3, -4)<br> help plz:)
AVprozaik [17]

Answer:

let \: slope \: be \: s \\ s =  \frac{( {y}^{1} -  {y}^{o} ) }{( {x}^{1} -  {x}^{o} ) }  \\ s =  \frac{( - 4 - 2)}{( - 3 - 3)}  \\ s =  \frac{ - 6}{ - 6}  \\ s = 1

8 0
3 years ago
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