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alexandr1967 [171]

3 years ago

12

Alexi opens his favorite mathematics puzzle book and notes that the product of the page numbers facing home is 1,332. Find the s

um of these two page numbers

1 answer:

Trava [24]3 years ago

3 0

The answer I think would be 66'6

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Identify the slope and y-intercept of the line y=-6x+4

frutty [35]

Answer:

Step-by-step explanation:

you have to use y=mx+b

5 0

4 years ago

Read 2 more answers

What is the area of a parallelogram with a base of 20 cm and a height of 12 cm?

AURORKA [14]

62.8cm^2 I think that's the answer

6 0

3 years ago

Need help with calculus asap with steps

Tasya [4]

Answer:

p=7/2

Step-by-step explanation:

Rember that a p series can be represented by

$\frac{1}{k {}^{p} }$

Here, notice that

$\frac{1}{8 \sqrt{2} } = \frac{1}{2 {}^{3} \sqrt{2} } = \frac{1}{2 {}^{3} \times 2 {}^{ \frac{1}{2} } } = \frac{1}{2 {}^{ \frac{7}{2} } }$

This is true for all parts of the series because

$27 \sqrt{3} = 3 {}^{ \frac{7}{2} }$

So p=7/2

3 0

3 years ago

Write the standard equation for the circle whose center is at (6,2) and whose radius is 2.

Grace [21]

Answer:

$(x - 6)^2 + (y - 2)^2 = 2^2$ .

Step-by-step explanation:

In general, let $(a,\, b)$ denote the center of a given circle. Let $r$ denote the radius of that circle. The standard equation for that circle would be:

$(x - a)^2 + (y - b)^2 = r^2$ .

The circle in this question is centered at $(6,\, 2)$ .

$6$ is the $x$ -coordinate of the center of this circle. $a = 6$ .
$2$ is the $y$ -coordinate of the center of this circle. $b = 2$ .

The radius of this circle is $2$ . Therefore, $r = 2$ .

Hence, the standard equation for this circle would be:

$(x - 6)^2 + (y - 2)^2 = 2^2$ .

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3 years ago

A function is defined as {(0, 1), (2, 3), (5, 8), (7, 2)}. Isaac is asked to create one more ordered pair for the function. Whic

svet-max [94.6K]

Answer:

2

Step-by-step explanation:

3 0

4 years ago