Answer:
The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
The right answer is B.
Step-by-step explanation:
According to the given data we have the following:
sample size, h=600
probability against increase tax p=0.45
The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.
We find that P(P>360/600)=P(P>0.6)
The sample proposition of p is approximately normally distributed mith mean p=0.45
standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600
If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)
Now, P(P>0.6)=P(<u>P-P</u> > <u>0.6-0.45)</u>
σ √0.45*0.55/600
=P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
1. 5 and E, 6 and F, 7 and D, 8 and A, 9 and G
Answer:
4x^3 - 15x^2 - 10x + 24
Step-by-step explanation:
FOIL (x-4)(4x^2+x-6)
= x(4x^2+x-6) -4(4x^2+x-6)
= 4x^3+x^2-6x-16x^2-4x+24
=4x^3-15x^2-10x+24
Answer:
less because it equals 0.85
Step-by-step explanation:
