No, I am not in active recovery from a substance use disorder (addiction). Active recovery is defined as being free from an alcohol or other drug use disorder or no longer using alcohol or other drugs is a true statement.
<h3>What does it mean to be in addiction recovery?</h3>
The statement implies that a person is working very hard to be successful in handling their addiction and getting back control of your life.
Note that it is not an easy road but one can overcome. Therefore, my response is No, I am not in active recovery from a substance use disorder (addiction) because i do not drink it. Active recovery is defined as being free from an alcohol or other drug use disorder or no longer using alcohol or other drugs is a true statement.
Learn more about Active recovery from
brainly.com/question/28027699
#SPJ1
Answer:
One best way to prevent from getting some emails from Brainly that are a bit annoying when you get there notifications from there, here are some ways you can get rid of those notifications below;
At the More options icon you can press it and if you see the word unsubscribe you can press it. The picture above shows a part of the instruction. This more options icon is :
At the More options icon you can also press block and you will no longer receive a notification from this app. thats the best i can do Explanation:
The two extensions in scratch are correctly matched to their accessibility goals Translate extension and Text to speech extension.
<h3>What are Scratch Extensions?</h3>
Scratch extensions are known to be used in an interface with external hardware and information outside of the Scratch website via new blocks.
Note that The two extensions in scratch are correctly matched to their accessibility goals Translate extension and Text to speech extension.
Learn more about scratch from
brainly.com/question/25720264
#SPJ1
Explanation:
num1= print("Enter a number :")
num2 = print("Enter a number :")
sum = num1 + num2
print(sum)
def pig_latin(word):
if word[0].lower() in 'aeiou':
word = word + 'way'
else:
t=''
for x in range(len(word)):
if word[x].lower() in 'aeiou':
break
if word[x].lower() == 'y' and x>0:
break
else:
t+=word[x].lower()
if word[0].isupper():
word = word[len(t):]+word[:len(t)].lower()+'ay'
word = word.title()
else:
word = word[len(t):]+word[:len(t)].lower()+'ay'
return word
word = 'test'
pl = pig_latin(word)
print(pl)
I wrote my code in python 3.8. I hope this helps.
