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melisa1 [442]
3 years ago
12

A custom date format set for a date/time field that contains the symbols mmm/dd/yy would display the date as ____.

Computers and Technology
1 answer:
Lena [83]3 years ago
5 0
Format for date is: mm/dd/yy
mm means month
dd means day
and
yy   means year.
Like: mm/dd/yy  12 / 15 / 2017    
December 15, 2017.
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Write a single instruction that inverts bits 5 and 6 in the bl register
katrin [286]

The single instruction that can inverts bits 5 and 6 in the bl register is xor bl,1100000b.

<h3>What is single instruction?</h3>

Single Instruction is a term that connote all the data streams are said to be processed though the use of the same compute logic.

Note that in the case above, the single instruction that can inverts bits 5 and 6 in the bl register is xor bl,1100000b.

Learn more about bits from

brainly.com/question/19667078

#SPJ12

5 0
2 years ago
Write a loop that reads c-strings from standard input where the c-string is either "land", "air", or "water". The loop terminate
Anvisha [2.4K]

Answer:

I am writing a C++ code.        

#include <iostream> // for input output functions

using namespace std; // identifies objects like cin cout

int main() { //start of main() function body

string c_string; // stores the string entered by user from land water or air

int land=0; // contains the number of times land string is read in

int air=0; //contains the number of times air string is read in

int water = 0; //contains the number of times water string is read in

cin>>c_string; //reads the string entered by user from air water or land

/*while loop continues to execute until user enters xxxxx or maximum length of a string exceeds 8 */

while(c_string!= "xxxxx" && c_string.length()<=8) {

if(c_string=="land"){ // if string entered by user is land

land = land + 1;} //counts and increments each occurrence of land string by 1

else if(c_string=="air"){// if string entered by user is air

air = air + 1;}// counts and increments each occurrence of string air by 1

else if(c_string=="water"){// if string entered by user is water

water = water + 1;}//counts and increments each occurrence of air by 1

cin>>c_string;}

/* keeps reading the string entered by user from land air or water, until the loop breaks after the user enters xxxxx or user enters a string whose length is greater than 8 */

//prints the number of times land, air and water are read in

cout << "land:"<<land;

cout << endl<<"air:"<<air;

cout << endl<< "water:"<<water; }                      

                                                                                     

Explanation:

Everything is well explained in the comments above.

The program prompts the user to input strings. These strings are either land air or water. The while loop continues to read the input strings until user enters xxxxx or the string entered by user exceeds the length 8. Both these terminating conditions are added in the while loop. After the loop terminates, the number of times land, air and water strings are read is displayed on the output screen. Any other string entered by user other than these 3 is ignored. The program along with the output is attached.

3 0
3 years ago
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For f
julia-pushkina [17]

Complete Question:

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

Answer:

a) 51.2 msec.  b) 5.12 msec

Explanation:

If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

  • Tw = K*512* bit time

The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

a) BW  = 1 Mbps = 10⁶ bps

⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

b) BW = 10 Mbps = 10⁷ bps

⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec

5 0
3 years ago
Help. serious help. the acc im using right now cant be ridded of by myself from being unable to have a pass. i need to contact a
anzhelika [568]

Answer:

Can't really help you... But you can try emailing support.

7 0
2 years ago
Which of the following statements are true regarding Steve Jobs and Steve Wozniak? Select 3 options.
Furkat [3]

Answer:

1. Both Steve Jobs and Steve Wozniak raised $1000 by selling personal items, so that they could start Apple.

2. Steve Wozniak worked for Hewlett Packard designing calculators before starting Apple.

4. Steve Jobs never learned to code and primarily focused on design.

Explanation:

I just took the test.

8 0
3 years ago
Read 2 more answers
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