1.55 x10 to the power of 9
9
1.55x10
should look something like that
7/20= .35 and .4 can also be .40 so rose bought more ginger
Answer:
There is no unique solution to this problem.
There are infinitely many solutions to this problem.
Step-by-step explanation:
Let B denotes broccoli crop
Let S denotes spinach crop
Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.
Mathematically,
6B + 9S = 93 eq. 1
This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.
Mathematically,
2B + 3S = 31
2B = 31 - 3S
B = (31 - 3S)/2 eq. 2
Substitute eq. 2 into eq. 1
6B + 9S = 93
6[(31 - 3S)/2] + 9S = 93
3(31 - 3S) + 9S = 93
93 - 9S + 9S = 93
- 9S + 9S = 93 - 93
0 = 0
Therefore, there is no unique solution to this problem.
Which means that there are infinitely many solutions to this problem.
He's correct
there is exactly 1760 yards in a mile
Answer:
The number of mosquitoes is maximum for 6.5 inches rainfall.
Step-by-step explanation:
The given function is
.... (1)
where, M(x) is number of mosquitoes in millions and x the June rainfall in inches.
We need to find the rainfall that produces the maximum number of mosquitoes.
Differential the above function with respect to x.
.... (2)
Equate first derivative equal to 0.
Differential function (2) with respect to x.
Double derivative is negative. So, the value of function is maximum at x=6.5.
Therefore, the number of mosquitoes is maximum for 6.5 inches rainfall.
