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Law Incorporation [45]
3 years ago
12

Which is an exponential decay function?

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Step-by-step explanation:

exponential decay functions are written in the form :

y=ab^{x}

where b is less than 1

if we look at the 3rd choice and consider the term on the right.

(8/7)^{-x}

= (7/8)^{x}

If we compare this to the general form above,

b = 7/8 (which is less than 1)

hence the 3rd choice is correct.

ipn [44]3 years ago
8 0
<h2>Answer:</h2>

The function which is an exponential decay function is:

                       f(x)=\dfrac{3}{2}(\dfrac{8}{7})^{-x}

<h2>Step-by-step explanation:</h2>

We know that an exponential  function is in the form of:

          f(x)=ab^x

where a>0 and  if 0<b<1 then the function is a exponential decay function.

and if b>1 then the function is a exponential growth function.

a)

f(x)=\dfrac{3}{4}(\dfrac{7}{4})^x

Here

b=\dfrac{7}{4}>1

Hence, the function is a exponential growth function.

b)

f(x)=\dfrac{2}{3}(\dfrac{4}{5})^{-x}

We know that:

a^{-x}=(\dfrac{1}{a})^x

Hence, we have the function f(x) as:

f(x)=\dfrac{2}{3}(\dfrac{5}{4})^x

Here

b=\dfrac{5}{4}>1

Hence, the function is a exponential growth function.

c)

f(x)=\dfrac{3}{2}(\dfrac{8}{7})^{-x}

We know that:

a^{-x}=(\dfrac{1}{a})^x

Hence, we have the function f(x) as:

f(x)=\dfrac{3}{2}(\dfrac{7}{8})^x

Here

b=\dfrac{7}{8}

Hence, the function is a exponential decay function.

d)

f(x)=\dfrac{1}{3}(\dfrac{9}{2})^x

Here

b=\dfrac{9}{2}>1

Hence, the function is a exponential growth function.

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