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Vinil7 [7]
3 years ago
13

Construct a regular hexagon with vertex A inscribed in the given circle

Mathematics
1 answer:
sweet [91]3 years ago
4 0

Im not sure if this is right but.

Make the diameter by putting the line on points A and C. Then put the middle of the tool on point A and make the width to point C and draw a circle. Do the same for point B (other side of point A) without changing the width. Then plot the lines where the circles intersect and you have a hexagon :)


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A rectangle has a length that is 2 meters more than the width. The area of the rectangle is 288 square meters. Find the dimensio
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Answer:

L = 18 and w = 16

Step-by-step explanation:

The area of a rectangle is found by A = l*w. Since the length here is 2 more than the width or 2 + w and the width is w, substitute these values and A = 288 to solve for w.

A = l*w\\288 = w(2+w)\\288 = w^2 + 2w

To solve for w, move 288 to the other side by subtraction. Then factor and solve.

w^2 + 2w  - 288 = 0 \\(w +18)(w-16) = 0\\

Set each factor equal to 0 and solve.

w - 16 = 0 so w = 16

w + 18 = 0 so w = -18

Since w is a side length and length/distance cannot be negative, then w = 16 is the width of the rectangle.

This means the length is 16 + 2 = 18.

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